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3 years ago

Which of the following provides evidence that geologic activity occurred in the past on Earth's Moon?

Physics

1 answer:

Bingel [31]3 years ago

6 0

Answer: d) the presence of solidified lava flows on the Moon

Explanation:

A geological activity means an occurrence of event such as volcanic eruption, earthquake, sedimentation, erosion etc. The revolution of the Moon around the Earth , the axial tilt of the Moon or the phases of the Moon are not surface features. hence, these events cannot provide the evidence of geological activity in the past of Moon.

The surface features of moon such as Mares, Craters, mountains, Rays and rills are the proof of some geological activity on the Moon. Mares are the dark patches on the moon's surface formed of solidified lava. Due to negligible atmosphere on the moon, the meteors strike its surface and cause craters to form. Thus, the correct answer is d.

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A 7 kg ball of clay traveling at 12 m/s collides with a 25 kg ball of clay traveling in the

ANEK [815]

Answer:

Given: 

m1 = 7 kg

V1 = 12 m/s

m2 = 25 kg

V2 = 6 m/s

To find:

Combined speed of two balls stick together after collision V = ?

Solution:

According to law of conservation of momentum,

m1V1 + m2V2 = (m1+m2)V

7×12 + 25×6 = (7+25)V

84 + 150 = 32V

V = 234/32

V = 7.31 m/s

Combined speed of two ball is 7.31 m/s

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4 0

2 years ago

Sport is an attractive activity for young people, and is often used as a draw card to recruit children and .....................

Nataliya [291]

Young people

Explanation:

cuz old people can't do sports

3 0

2 years ago

The United States and South Korean soccer teams are playing in the first round of the World Cup. An American kicks the ball, giv

garik1379 [7]

Answer:

Vf = 3.67 [m/s]

Explanation:

To solve this problem we must use the following equation of kinematics.

$v_{f} ^{2} =v_{i} ^{2} -(2*a*x)$

where:

Vf = final velocity [m/s]

Vi = initial velocity = 4.3 [m/s]

a = acceleration or desacceleration = 0.5 [m/s²]

x = distance = 5 [m]

Note: The negative sign in the above equation means that the velocity of the ball is decreasing (desacceleration).

Now replacing:

Vf² = (4.3)² - (2*0.5*5)

Vf² = 18.49 - 5

Vf² = 13.49

using the square root, we have.

Vf = 3.67 [m/s]

8 0

2 years ago

The smallest shift you can reliably measure on the screen is about 0.2 grid units. This shift corresponds to the precision of po

creativ13 [48]

Answer:

The distance is $d = 1.5 *10^{15} \ km$

Explanation:

From the question we are told that

The smallest shift is $d = 0.2 \ grid \ units$

Generally a grid unit is $\frac{1}{10}$ of an arcsec

This implies that 0.2 grid unit is $k = \frac{0.2}{10} = 0.02 \ arc sec$

The maximum distance at which a star can be located and still have a measurable parallax is mathematically represented as

$d = \frac{1}{k}$

substituting values

$d = \frac{1}{0.02}$

$d = 50 \ parsec$

Note $1 \ parsec \ \to 3.26 \ light \ year \ \to 3.086*10^{13} \ km$

So $d = 50 * 3.08 *10^{13}$

$d = 1.5 *10^{15} \ km$

3 0

3 years ago

A very powerful vacuum cleaner which has a hose of circular cross section can lift a brick of mass 12 kg when the hose is placed

valkas [14]

Answer:

A). 1.9 cm

Explanation:

m = Mass of brick = 12 kg

g = Acceleration due to gravity = 9.81 m/s²

r = Radius of hose

A = Area = $\pi r^2$

F = Force = $mg$

Let us assume that the pressure required to lift the brick would be atmospheric pressure

$P=\dfrac{F}{A}\\\Rightarrow P=\dfrac{F}{\pi r^2}\\\Rightarrow r=\sqrt{\dfrac{F}{\pi P}}\\\Rightarrow r=\sqrt{\dfrac{12\times 9.81}{\pi\times 101325}}\\\Rightarrow r=0.01923\ m=1.9\ cm$

The radius of the hose should be 1.9 cm

6 0

3 years ago