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Ymorist [56]
3 years ago
10

Which of the following provides evidence that geologic activity occurred in the past on Earth's Moon?

Physics
1 answer:
Bingel [31]3 years ago
6 0

Answer: d) the presence of solidified lava flows on the Moon

Explanation:

A geological activity means an occurrence of event such as volcanic eruption, earthquake, sedimentation, erosion etc. The revolution of the Moon around the Earth , the axial tilt of the Moon  or the phases of the Moon are not surface features. hence, these events cannot provide the evidence of geological activity in the past of Moon.

The surface features of moon such as Mares, Craters, mountains, Rays and rills are the proof of some geological activity on the Moon. Mares are the dark patches on the moon's surface formed of solidified lava. Due to negligible atmosphere on the moon, the meteors strike its surface and cause craters to form. Thus, the correct answer is d.

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23. A pogo stick has a spring with a force constant of 2.50×104N/m , which can be compressed 12.0 cm. To what maximum height can
tensa zangetsu [6.8K]

Answer:

The maximum height the child can jump on the stick

h=0.459m

Explanation:

Energy conservation

Energy kinetic = Work

The energy the child do get the height jump is proportional at the distance and the consta can be compressed so:

\frac{1}{2}*k*x^{2} =m*g*h\\k=2.50x10^{4} \frac{N}{m}\\x=12cm*\frac{1m}{100cm}=0.12m\\h=\frac{k*x^{2} }{2*m*g}\\h=\frac{2.50x10^{4}\frac{N}{m}*(0.12m)^{2} }{2*40kg*9.8\frac{m}{s^{2}}}\\h=\frac{360\frac{N}{m}m^{2} }{784N}\\h=0.459m

8 0
4 years ago
Sound waves have 4 basic properties including amplitude, wavelength and
igomit [66]

D) Pitch since it does not measure distance, media, or speed (because it only has one speed)

7 0
3 years ago
What is the gravitational field strength at a distance of 60.0 km above the surface of the earth
zloy xaker [14]

Answer:

g=9.64m/s^2.

Explanation:

Gravitational field strength (in other words, gravitational acceleration) is given as follows:g=GMR2g=R2GM​where G=6.674×10−11m3kg⋅s2G=6.674×10−11kg⋅s2m3​ is the gravitational constant, M=5.972×1024kgM=5.972×1024kg is the mass of the Earth, and R=6.371×106m+0.06×106m=6.431×106mR=6.371×106m+0.06×106m=6.431×106m is the distance from the center of the Earth to the required point above the surface (radius plus 60 km).

6 0
2 years ago
What is the speed of a person that walk 400 meters in 1900 seconds
Nezavi [6.7K]

Answer:

Explanation:

.

6 0
3 years ago
A certain airplane has a speed of 290.0 km/h and is diving at an angle of 0 : 30.0" below the horizontal when the pilot releases
prisoha [69]

Answer:

10.03 s is the time the decoy is in the air

Explanation:

From the information given we know:

  • \theta_{0}=-30 because is measured clockwise from horizontal.
  • The initial speed of the decoy is the plane's speed at the moment of release v_{0}=290 \:\frac{km}{h}

We will need to work in meters and m/s, so 290 \:\frac{km}{h} \cdot \frac{1000 \:m}{km} \cdot \frac{1\:h}{3600\:s} = 80.56 \:\frac{m}{s}

The horizontal motion of a projectile is given by:

x-x_{0}=v_{0x}\cdot t

because v_{0x}=v_0cos(\theta_{0}), this becomes

x-x_{0}=(v_0cos(\theta_{0}))\cdot t

We have that \Delta x= 700\:m, solving for <em>t, </em>we have

t=\frac{\Delta x}{v_{0}cos\theta_{0}} \\t=\frac{700 \:m}{(80.56 \:\frac{m}{s} )\cdot cos(-30)} \\t= 10.03 \:s

5 0
3 years ago
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