All categories

3 years ago

SHOW WORK:

Mathematics

1 answer:

fomenos3 years ago

6 0

Answer:

Expected population in 2015: 19,152.58 or 19,000 people

Step-by-step explanation:

Given the decreasing rate of 2.5% per year, and a population of 28,000 in the year 2000:

We can solve for the rate of decrease by using the formula:

$A = a(1 - r )^{t}$

where:

A = population by year 2015

a = initial population (in year 2000) = 28,000

r = rate of change (decrease by 2.5% annually or 0.025)

t = time (in number of years) = 15

Plug in these given values into the formula:

$A = a(1 - r )^{t}$

$A = 28,000(1 - 0.025 )^{15}$

$A = 28,000(0.975)^{15}$

A = 28,000(0.684)

A = 19,152.58 or about 19,000 people in 2015

You might be interested in

the height of the smaller box is 80% of the height of the larger box, while the other two dimensions are the same for both boxes

Bogdan [553]

Let
z-----------> the height of the larger box
x-----------> the length side of the box (smaller and larger box)
y-----------> the width side of the box (smaller and larger box)

volume larger box=x*y*z
volume smaller box=x*y*(0.80z)----> 0.80[x*y*z]

the difference in the volume of these two boxes=[x*y*z]*(1-0.80)
the difference in the volume of these two boxes=0.20*[x*y*z]

The height of the smaller box is 12 in
so
z*0.8=12--------> z=12/0.8---------> z=15 in
x=7 3/4 in--------> (7*4+3)/4---------> 31/4 in
y= 2 in

the difference in the volume of these two boxes=0.20*[(31/4)*2*15]
the difference in the volume of these two boxes=46.5 in³

the answer is
46.5 in³

7 0

4 years ago

Read 2 more answers

What pecent is 425 of 500

mars1129 [50]

Answer: 85

Step-by-step explanation:

Kid.

7 0

3 years ago

Read 2 more answers

The manufacturer of an airport baggage scanning machine claims it can handle an average of 553 bags per hour. (a-1) At α = .05 i

timurjin [86]

Answer:

H1 : μ < 553. Reject H1 if tcalc > –1.753.

There is not enough evidence to reject the manufacturer’s claim.

Step-by-step explanation:

We are given that the manufacturer of an airport baggage scanning machine claims it can handle an average of 553 bags per hour.

A sample of 16 randomly chosen hours with a mean of 533 and a standard deviation of 47 is given.

Let $\mu$ = average bags that an airport baggage scanning machine can handle.

SO, Null Hypothesis, $H_0$ : $\mu \geq$ 553 bags {means that the manufacturer’s claim is not overstated}

Alternate Hypothesis, $H_0$ : $\mu$ < 553 bags {means that the manufacturer’s claim is overstated}

The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = 533 bags

s = sample standard deviation = 47

n = sample of hours = 16

So, the test statistics = $\frac{533-553}{\frac{47}{\sqrt{16} } }$ ~ $t_1_5$

= -1.702

The value of t test statistics is -1.702.

Now, at 0.05 significance level the t table gives critical value of -1.753 at 15 degree of freedom for left-tailed test.

Since our test statistic is more than the critical value of t as -1.702 > -1.753, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the manufacturer’s claim is not overstated and an airport baggage scanning machine can handle an average of 553 bags per hour.

5 0

3 years ago

There are 350 students at GMS. if 14 students were absent, what percent is THERE

artcher [175]

I hope this helps you

if in 350 students are 14 students were absent

in 100 students are ?

?.350=100.4

?=400/360

?=1.14%

4 0

3 years ago

Read 2 more answers

Write an expression that is equivalent to 30(x + y + 1)

xz_007 [3.2K]

Answer:30x+30y+30

Step-by-step explanation: