<span>The purpose of the overload keyword in the ip nat inside source list 1 pool nat_pool overload command is that </span>It allows many inside hosts to share one or a few inside global addresses.
Answer:
Offset bits: 3-bits
Set number of cache: 12-bits
Tag bits: 7-bits
22-bit physical address
Explanation:
Since the system is 32K so,
=2⁵.2¹⁰
=2¹⁵
As we know that it is 8-way set associative so,
=2¹⁵/2³
=2¹⁵⁻³
=2¹²
2¹² are cache blocks
22-bit physical address
Off-set bits are 3 as they are calulated from 8-way set associative information.
Set number of cache : 12-bits
For tag-bits:
Add off-set bits and cache bits and subtract from the total bits of physical address.
=22 - (12+3)
=22 - 15
=7
I think the answer is one fourth.
Because usually only that part is visible in a stand. It usually contains the name of the magazine and a little bit of illustration gives an idea about what it is about.
Answer:
if ((b*b - 4*a*c)<0)
cout << "no real solutions";
return;
Explanation:
To check if "b squared" – 4ac is negative, we use the expression if ((b*b - 4*a*c)<0). This expression evaluates the 'bsquared' and substracts '4ac' from it. It then compares the resulting value with zero. if it is less than zero it means it is a negative number, so it executes the statement following cout << "no real solutions"; and returns
