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mixas84 [53]
3 years ago
7

Complete the table to investigate dilations of

Mathematics
1 answer:
weeeeeb [17]3 years ago
8 0

Answer:

a= 1

b= 3

c= 2

d= 2

e= 6

f= 8. These are the answers for the question. Love from Gauthmath

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(Can Someone Help Answer This Problem) + No Links
Alex17521 [72]

Answer:

50 + 100n  

Step-by-step explanation:

The cost is the cost of the visit plus the cost of the cavities

50 + 100n  where n is the number of cavities

6 0
3 years ago
Read 2 more answers
Solve for x:<br> 18x + 3x + 4 - 5 = 5(4x – 9
Luden [163]
Answer:
X= - 44
18x+3x+4-5=5(4x9
Collect like terms
21x+4-5=5(4x-9
More variable to the left hand side and change its sign
21x-20x-1=-45
Correct like terms
X=-45+1
Which is x=-44
4 0
3 years ago
(4.1.4) Let X and Y be Bernoulli random variables. Let Z = X + Y. a. Show that if X and Y cannot both be equal to 1, then Z is a
Fynjy0 [20]

Step-by-step explanation:

Given that,

a)

X ~ Bernoulli (p_x) and Y ~ Bernoulli (y_x)

X + Y = Z

The possible value for Z are Z = 0 when X = 0 and Y = 0

and Z = 1 when X = 0 and Y = 1 or when X = 1 and Y = 0

If X and Y can not be both equal to 1 , then the probability mass function of the random variable Z takes on the value of 0 for any value of Z other than 0 and 1,

Therefore Z is a Bernoulli random variable

b)

If X and Y can not be both equal to  1

then,

p_z = P(X=1 or Y=1)\\

p_z = P(X=1)+P(Y=1)-P(=1 and Y =1)

p_z = P(x=1)+P(Y=1)\\\\p_z=p_x+p_y

c)

If both X = 1 and Y = 1 then Z = 2

The possible values of the random variable Z are 0, 1 and 2.

since a  Bernoulli variable should be take on only values 0 and 1 the random variable Z does not have Bernoulli distribution

7 0
3 years ago
How do I do this when I first learn it
oksano4ka [1.4K]
You would put in 12 for x since there are 12 months in a year. Then you would multiply 12 by 35, and add 70.
3 0
3 years ago
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Find the mean, median, mode, and range of this data: 49, 49, 54, 55, 52, 49, 55. If necessary, round to the nearest tenth.
krok68 [10]

Answer:

Mean = 51.4.

Mode = 49.

Median = 52.

Range = 6.

Step-by-step explanation:

Mean = Sum of all observations / Number of observations.

Mean = (49+49+54+55+52+49+52)/7

Mean = 360/7

Mean = 51.4 (to the nearest tenth).

Mode = The most repeated values = 49 (repeated 3 times).

Range = Largest Value - Smallest Value = 55 - 49 = 6.

Median = The central value of the data.

First, arrange the data in the ascending order: 49, 49, 49, 52, 54, 55, 55.

It can be seen that the middle value is 52. Therefore, median = 52!!!

7 0
3 years ago
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