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mixas84 [53]
3 years ago
7

Complete the table to investigate dilations of

Mathematics
1 answer:
weeeeeb [17]3 years ago
8 0

Answer:

a= 1

b= 3

c= 2

d= 2

e= 6

f= 8. These are the answers for the question. Love from Gauthmath

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Hector has a floor plan showing his new house. On the floor plan, his bedroom is 3 inches wide and 3
Nat2105 [25]

<em><u>Question:</u></em>

Hector has a floor plan showing his new house. On the floor plan, his bedroom is 3 inches wide and 3 1/2 inches long. The scale of the floor plan is 1/4 inch = 1 foot. What is the actual length of Hector’s room?

<em><u>Answer:</u></em>

The actual length of Hector room is 14 foot

<em><u>Solution:</u></em>

Given that, On the floor plan, his bedroom is 3 inches wide and 3\frac{1}{2} inches long

<em><u>The scale of floor plan is given as:</u></em>

\frac{1}{4} \text{ inch} = 1 \text{ foot }

Therefore,

1 \text{ inch } = 4 \text{ foot}

To find: Actual length of floor

From given question,

length = 3\frac{1}{2} \text{ inches}

Converting the mixed fraction to improper fraction,

length = \frac{2 \times 3 + 1}{2} = \frac{7}{2} \text{ inches }

Since, 1 inch = 4 foot

\frac{7}{2} \text{ inches } = \frac{7}{2} \times 4 \text{ foot } = 14 \text{ foot }

Thus actual length of Hector room is 14 foot

6 0
3 years ago
What is the resulting equation when the expression for y in the second equation is substituted into the first equation?
Anni [7]

Answer: 3x + 6 -4x = 1

Simplify to -x + 6 = 1 because 3x - 4x = -1x

5 0
3 years ago
What is the math for 4×(5+2) ?​
Rzqust [24]

Answer:

28

Step-by-step explanation:

since the 5+2 is in parenthesis(don't know how to spell it its these things >( ) if you didn't know) you have to do 5+2 1st so thats 7 then you do 4*7 which is 28

8 0
3 years ago
If a jogger runs 2 miles and burns 185 calories, how many calories would he burn if he jogged 3 miles?
aliina [53]

The total amount of calories burnt in jogging 2 miles = 185 calories

We have to determine the number of calories burned in jogging 3 miles.

Firstly, we will determine the amount of calories burnt in jogging 1 mile. We will use unitary method to evaluate this.

So, the total amount of calories burnt in jogging 1 mile = 185 \div 2

= 92.5 calories

So, the amount of calories burnt in 3 miles = 3 \times 92.5

= 277.5 calories

Therefore, 277.5 calories are burned in jogging 3 miles.

6 0
3 years ago
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Hey help me with this what's the answer of number 12
PtichkaEL [24]
What was the instructions given
6 0
3 years ago
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