Answer:
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
Step-by-step explanation:
If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -
x = ( 30 cos 20° )( time ),
y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2
To determine " ( 30 cos 20° )( time ) " you would do the following calculations -
( x = 30 * 0.93... = ( About ) 28.01t
This represents our horizontal distance, respectively the vertical distance should be the following -
y = 30 * 0.34 - 4.9t^2,
( y = ( About ) 10.26t - 4.9t^2 + 2
In other words, our solution should be,
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
<u><em>These are are parametric equations</em></u>
Answer:
x=4√5
y=12
z=6√5
is your answer look it once
3.5 pounds equals 56 ounces
Answer:
x=8y/3-4
Step-by-step explanation:
What we have to do to solve for X into re arrange the equation so that X is by itself on one side of the equation. To start we will divide both sides by 3/8 to move it away from the X side and we get
8y/3=x+4 then we will subtract both sides by 4 to get x all by itself
8y/3-4=x
I hope this helps and please don't hesitate to ask if there is anything still unclear!
C) 2
1) Given the table, let's find out that missing data picking 2 points (2,-10) and (6,-4)
Since we have the slope, let's work on finding the linear coefficient
plugging point (2,-10) into that:
y= mx +b
-10 =3/2(2) +b
-10 =6/2 +b
-10= 3 +b
-10-3 =b
b= -13
2) So the rule of that function is y= 3/2x -13
Plugging x= 10 we have
y= 3/2(10) -13
y=2
3) So the missing y-coordinate is 2.
