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zheka24 [161]
3 years ago
7

..1+4=5. 2+5=12. 3+6=21. 8+11=40 or this could be 96 which is right and why

Mathematics
1 answer:
andre [41]3 years ago
7 0
Multiply the numbers being added then add the first number. 4X1=4, 4+1=5.
2X5=10, 10+2=12. 11X8=88, 88+8=96. I'm not sure how to get 40, though. 
Hope I could help.
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Which is an exponential decay function f (x)=3/4 (7/4)x f (x)=2/3 (4/5)-x. F (x)=3/2 (8/7)-x f (x)=1/3 (9/2)x
dsp73
The given functions are
1.\, f(x)= \frac{3}{4}( \frac{7}{4})^{x} \\ \\2.\,f(x)= \frac{2}{3}( \frac{4}{5} ) ^{-x}\\\\3.\, f(x)= \frac{3}{2} ( \frac{8}{7} )^{-x}\\\\4.\,f(x)= \frac{1}{3} ( \frac{9}{2} )^{x}

Evaluate the functions. 
1. Because 7/4 > 1 and the exponent is positive,
   the function does not decay.
2.Because 4/5 < 1 and the exponent is negative,
    the function does not decay.
3. Because 8/7 > 1 and the exponent is negative,
    the function decays.
4. Because 9/2 > 1 and the exponent is positive,
    the function does not decay.

A composite plot the functions verifies the answer.

Answer: f(x)= \frac{3}{2} ( \frac{8}{7} )^{-x}

7 0
4 years ago
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I need this math question solved fast please!!!
beks73 [17]

Answer:

5 2/3

Step-by-step explanation:

3 0
3 years ago
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Micah can do 75 push up in 3 minutes Edward Lowe can do 130 push-ups in 5 minutes are these rates equivalent
IrinaK [193]
No because Edward can do 26 push-ups per minute while Micah can only do 25 push-ups per minute
6 0
4 years ago
P is the point on the line 2x+y-10=0 such that the length of OP, the line segment from the origin O to P, is a minimum. Find the
nirvana33 [79]
The minimum distance is the perpendicular distance. So establish the distance from the origin to the line using the distance formula.
The distance here is: <span><span>d2</span>=(x−0<span>)^2</span>+(y−0<span>)^2
</span>                                      =<span>x^2</span>+<span>y^2
</span></span>
To minimize this function d^2 subject to the constraint, <span>2x+y−10=0
</span>If we substitute, the y-values the distance function can take will be related to the x-values by the line:<span>y=10−2x 
</span>You can substitute this in for y in the distance function and take the derivative:
<span>d=sqrt [<span><span><span>x2</span>+(10−2x<span>)^2]
</span></span></span></span>
d′=1/2 (5x2−40x+100)^(−1/2)   (10x−40)<span>
</span>Setting the derivative to zero to find optimal x,
<span><span>d′</span>=0→10x−40=0→x=4
</span>
This will be the x-value on the line such that the distance between the origin and line will be EITHER a maximum or minimum (technically, it should be checked afterward).
For x = 4, the corresponding y-value is found from the equation of the line (since we need the corresponding y-value on the line for this x-value).
 
Then y = 10 - 2(4) = 2.
 So the point, P, is (4,2).
8 0
4 years ago
The buyer for a convenience store negotiates a single discount for a gallon of yellow shaved ice flavoring, based on the change
Komok [63]

Answer:

$8.88

Step-by-step explanation:

12.00 - 26%(3.12)= $8.88

7 0
3 years ago
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