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mart [117]
3 years ago
12

The first rule is subtract 6 starting from 48. The second rule is subtract 3 starting from 30. What is the second ordered pair u

sing the terms in each sequence? (42, 27) (36, 24) (48, 30) (30, 21)
Mathematics
2 answers:
Natasha2012 [34]3 years ago
6 0

Answer:

(42,48)?

Step-by-step explanation:

Marizza181 [45]3 years ago
6 0

Answer:

(42, 27)

Step-by-step explanation:

The first rule is to do 48-6, so this would be the x- axis.

The second rule is to do 30-3, so this would be the y-axis.

The first ordered pair would be (48, 30), then the second ordered pair would be (42, 27).  

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P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

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Step-by-step explanation:

The exact way to solve this problem is using the binomial distribution, assuming that our random variable of interest is "number of students living in apartments" represented by X and X \sim Bin(n=600, p =0.4)

And we want this probability:

P(200 \leq X \leq 400) [tex]In order to find this probability we can use the foloowing excel code:"=BINOM.DIST(400,600,0.4,TRUE)-BINOM.DIST(199,600,0.4,TRUE)"And we got:[tex] P(200 \leq X \leq 400) =0.999675[tex]But for this case the problem says that we need to approximate, so then we can use the normal approximation to the normal distribution. We need to check the conditions in order to use the normal approximation.
[tex]np=600*0.4=240\geq 10

n(1-p)=600*(1-0.4)=360 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=600*0.4=240

\sigma=\sqrt{np(1-p)}=\sqrt{600*0.4(1-0.4)}=12

And then X \sim N (\mu = 240, \sigma= 12)

And we are interested on the following probability:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

6 0
3 years ago
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