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Alina [70]
3 years ago
7

Please help!! Take a factor out of the square root:

Mathematics
1 answer:
Doss [256]3 years ago
7 0

Answer:

2a times the sq root of 2a or 2a (2a)**1/2

Step-by-step explanation:

(8a**3)**1/2 =

((2**2 * 2) (a**2) (a))**1/2 then take out and squares

2a (2a)**1/2

or 2a times the sq root of 2a

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Patrick is constructing the circumscribed circle for △RST. Which construction could be his first step?
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When c=3 and d=7<br> 21c + 2d - |-11|d
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0

Step-by-step explanation:

21(3) +2(7) - 11(7)             because the absolute value of -11 is 11

63+14-77

=0

8 0
3 years ago
In two or more complete sentences, explain how to find the average rate of change of a function.
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3 0
3 years ago
Find the value of k so that 48x-ky=11 and (k+2)x+16y=-19 are perpendicular lines.
Rufina [12.5K]

Answer: k = -1 +/- √769

<u>Step-by-step explanation:</u>

48x - ky = 11

<u>-48x        </u>  <u> -48x</u>

         -ky = -48x + 11

         \frac{-ky}{-k} = \frac{-48x}{-k} + \frac{11}{-k}    

           y =\frac{48x}{k} - \frac{11}{k}

Slope: \frac{48}{k}

*************************************************************************

 (k + 2)x + 16y = -19

<u>- (k + 2)x          </u>   -<u>(k + 2)x </u>

                 16y = -(k + 2)x - 19

                  \frac{16y}{16} = -\frac{(k + 2)x}{16} - \frac{19}{16}

                  y = -\frac{(k + 2)x}{16} - \frac{19}{16}

Slope: -\frac{(k + 2)}{16}

**********************************************************************************

\frac{48}{k} and -\frac{(k + 2)}{16} are perpendicular so they have opposite signs and are reciprocals of each other.  When multiplied by its reciprocal, their product equals -1.

-\frac{(k + 2)}{16} *  \frac{k}{48} = -1

\frac{(k + 2)k}{16(48)} = 1

Cross multiply, then solve for the variable.

(k + 2)(k) = 16(48)

k² + 2k - 768 = 0

Use quadratic formula to solve:

k = -1 +/- √769



5 0
3 years ago
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