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Ann [662]
3 years ago
5

Which expression is equivalent to (256x^16)^1/4 A.4x^2 B.4x^4 C. 64x^2 D. 64x^4

Mathematics
2 answers:
antiseptic1488 [7]3 years ago
6 0

Given expression: (256x^{16})^{1/4}.

\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n

=256^{\frac{1}{4}}\left(x^{16}\right)^{\frac{1}{4}}

256=4^4

256^{\frac{1}{4}}=\left(4^4\right)^{\frac{1}{4}}=4

\left(x^{16}\right)^{\frac{1}{4}}=x^{16\cdot \frac{1}{4}}=x^4

(256x^{16})^{1/4} =4x^4

<h3>Therefore, correct option is B option : B.4x^4</h3>
iren2701 [21]3 years ago
3 0

Answer:  The correct option is (B) 4x^4.

Step-by-step explanation:  We are given to select the correct expression that is equivalent to the expression below:

E=(256x^{16})^\frac{1}{4}.

We will be using the following properties of exponents:

(i)~(a^b)^c=a^{b\times c},\\\\(ii)~(ab)^c=a^cb^c.

We have

E\\\\=(256x^{16})^\frac{1}{4}\\\\=(4^4x^{16})^\frac{1}{4}\\\\=(4^4)^\frac{1}{4}(x^{16}^\frac{1}{4})\\\\=4^{4\times\frac{1}{4}}x^{16\times\frac{1}{4}}\\\\=4x^4.

Therefore, the required equivalent expression is 4x^4.

Thus, (B) is the correct option.

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E=6c^2−2c−1<br><br> F=−4c^2+7c+5<br> ​<br> E+F=
IRINA_888 [86]

The answer of given equation is 2c^{2} + 5c +4

Step-by-step explanation:

By putting the given values of E and F we get,

E + F

=( 6c^{2}-2c-1) + (-4c^{2}+7c+5)

Here we will take the coefficient of same variable together

=(6c^{2}-4c^{2}) +( -2c +7c) +( -1+5)

=2c^{2} + 5c +4

Hope this helps you.

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4 0
3 years ago
Blake has to put up a fence around a pet pen which s rectangular. If the width is 23 feet and the perimeter is 114 feet. What is
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P = 114
W = 23

114 = 2(L + 23)
114 = 2L + 46
114 - 46 = 2L
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3 years ago
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Brandon is on one side of a river that is 50 m wide and wants to reach a point 300 m downstream on the opposite side as quickly
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Let P be Brandon's starting point and Q be the point directly across the river from P. 
<span>Now let R be the point where Brandon swims to on the opposite shore, and let </span>
<span>QR = x. Then he will swim a distance of sqrt(50^2 + x^2) meters and then run </span>
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<span>T = (1/2)*sqrt(2500 + x^2) + (1/6)*(300 - x). Now differentiate with respect to x: </span>

<span>dT/dx = (1/4)*(2500 + x^2)^(-1/2) *(2x) - (1/6). Now to find the critical points set </span>
<span>dT/dx = 0, which will be the case when </span>

<span>(x/2) / sqrt(2500 + x^2) = 1/6 ----> </span>

<span>3x = sqrt(2500 + x^2) ----> </span>

<span>9x^2 = 2500 + x^2 ----> 8x^2 = 2500 ---> x^2 = 625/2 ---> x = (25/2)*sqrt(2) m, </span>

<span>which is about 17.7 m downstream from Q. </span>

<span>Now d/dx(dT/dx) = 1250/(2500 + x^2) > 0 for x = 17.7, so by the second derivative </span>
<span>test the time of travel, T, is minimized at x = (25/2)*sqrt(2) m. So to find the </span>
<span>minimum travel time just plug this value of x into to equation for T: </span>

<span>T(x) = (1/2)*sqrt(2500 + x^2) + (1/6)*(300 - x) ----> </span>

<span>T((25/2)*sqrt(2)) = (1/2)*(sqrt(2500 + (625/2)) + (1/6)*(300 - (25/2)*sqrt(2)) = 73.57 s.</span><span>
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8 0
3 years ago
TVs are usually measured as a diagonal distance across the screen for screen measures 15.1 inches in height and 19 inches diagon
trasher [3.6K]

Answer:

11.53 inches

Step-by-step explanation:

Given data

Diagonal = 19 inches

Height=  15.1 inches

Let us apply the Pythagoras theorem

D^2= H^2+W^2

substitute

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361=228.01+W^2

361-228.01=W^2

132.99= W^2

W=√132.99

W=11.53 inches

Hence the width is 11.53 inches

5 0
3 years ago
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