So we know that the perimeter is 1260 feet and that the length is 100 more than the width, but we don't know that the width is.
So we're going to start with finding the width.

from there we need to combine like terms

now we have

From there, we will need to remove 100 from both sides, leaving us with

now we'll need to divide both sides by 2


We now know that the width is 580, or more simply put, x=580.
Finding the length will be the easy part, as we know that it is just 100 more than the width

If you want an easier way of finding the length, just subtract the width from the perimeter.

Leaving the final answer to be
Width = 580
Length = 680
Answer:



Step-by-step explanation:
Given
The table
First, we calculate the amount of schools


Solving (a): Probability of 75+ computers.
From the given table, schools with 75 or more computers have the population of:


The probability is calculated as:



Solving (b): Probability of less than 75 computers.
From the given table, schools with less than 75 computers have the population of:


The probability is calculated as:



Solving (c): Probability of less than 10 computers.
From the given table, schools with less than 100 computers have the population of:


The probability is calculated as:



Answer:
Part A). 25 feet
Part B). 16.25 feet
Step-by-step explanation:
Part A). By applying Pythagoras theorem in ΔABC,
AC² = AB² + BC²
AC² = (24)² + 7²
AC² = 576 + 49
AC = √625
= 25 feet
Part B). By applying Pythagoras theorem in ΔABC,
AC² = AB² + BC²
(25)² = (19)² + x²
625 = 361 + x²
x² = 625 - 361
x = √264
x = 16.25 feet
Answer:
If B is the midpoint, it means
AC=2AB
8= 2(3x-1)
8= 6x-2
8+2= 6x
10= 6x
x= 10/6
x= 1.67
Hope it helps :-)