Answer:
Distance= 6.6 miles
Bearing= N 62.854°W
Step-by-step explanation:
Let's determine angle b first
Angle b=20° (alternate angles)
Using cosine rule
Let the distance between the liner and the port be x
X² =8.8²+2.4²-2(8.8)(2.4)cos20
X²= 77.44 + 5.76-(39.69)
X²= 43.51
X= √43.51
X= 6.596
X= 6.6 miles
Let's determine the angles within the triangle using sine rule
2.4/sin b = 6.6/sin20
(2.4*sin20)/6.6= sin b
0.1244 = sin b
7.146= b°
Angle c= 180-20-7.146
Angle c= 152.854°
For the bearing
110+7.146= 117.146
180-117.146= 62.854°
Bearing= N 62.854°W
Answer:
Step-by-step explanation:
Roots: set y = x^2 + 8x + 12 = 0 and solve for x: x + 6 = 0, so x = -6 is one root. The other is x = -2. The corresponding points are (-6, 0) and (-2, 0).
y-intercept: Let x = 0. Then y = 12. The y-intercept is (0, 12).
Axis of symmetry: x = -b / (2a) => x = -8/(2*1) = -4: x = -4
Vertex y-value: evaluate y at x = - 4: (-4)^2 + 8(-4) + 12 = -4: (-4, -4)
Arbitrarily chosen x value: x = 1 => 1^2 + 8(1) + 12 = 21: (1, 21)
The five points are: (-6, 0) and (-2, 0), (0, 12), (-4, -4), (1, 21). The vertex is (-4, -4). The parabolic graph opens UP.
Answer:
d
Step-by-step explanation:
I think it’s 25 and two half’s
The hundredth is the second number to the right of the decimal point. Also, if the number directly to the right of it is 5 or larger, you will have to round up by one.
23.558 becomes 23.56.
