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3 years ago

Round to the nearest ten

Mathematics

2 answers:

Kipish [7]3 years ago

8 0

Answer:

Step-by-step explanation:

The given dimensions:

Height = 12 in

Radius = 9 in

Recall the cylinder volume formula: $V=\pi r^2h$

where r = radius and h = height

Using the dimensions stated above, plug in the values into the formula

$V=\pi 9^212\\9^2=81\\81\pi =254.4690049\\254.4690049*12=3053.628059\\V=3053.628059$

Finally, round answer to the nearest tenth

Your answer would be A.3053.6

Kitty [74]3 years ago

7 0

The answer is A I hope this helps

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a cell phone company plans to market a new smartphone. they have already sold 612 units durning the first week of the campaign.

Vadim26 [7]

The first term is 612.

The common ratio is 1.08 and

The recursive rule is $a_{n} = a^{n-1} \times r$

Step-by-step explanation:

the question to the problem is to write the values of the first term, common ratio, and expression for the recursive rule.

The first term :

In geometric sequence, the first term is given as $a_{1}$ .

⇒ $a_{1} = 612$

Now, the geometric sequence follows as 612, 661, ........

The common ratio (r) :

It is the ratio between two consecutive numbers in the sequence.

Therefore, to determine the common ratio, you just divide the number from the number preceding it in the sequence.

⇒ r = 661 divided by 612

⇒ r = 1.08

To find the recursive rule :

A geometric series is of the form a,ar,ar2,ar3,ar4,ar5........

Here, first term $a_{1} = a$ and other terms are obtained by multiplying by r.

Observe that each term is r times the previous term.
Hence to get nth term we multiply (n−1)th term by r .

The recursive rule is of the form $a_{n} = a^{n-1} \times r$

This is called recursive formula for geometric sequence.

We know that r = 1.08 and $a_{1}$ = 612.

To find the second term $a_{2}$ , use the recursive rule $a_{n} = a^{n-1} \times r$

⇒ $a_{2} = a^{2-1}\times r$

⇒ $a_{2} = a^{1}\times r$

⇒ $a_{2} = 612\times 1.08$

⇒ $a_{2} = 661$

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Whats 42.12500 rounded to the nearest whole number?

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