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vodka [1.7K]
3 years ago
5

At a party there were four large submarine sandwiches, all the same size. During the party, 2/3 of the chicken sandwhich, 3/4 of

the tuna sandwhich, 7/12 of the roast beast and 5/6 of the veggie sandwhich were eaten. Which sandwhich had the least amount left?
Mathematics
1 answer:
musickatia [10]3 years ago
8 0

Answer:

The answer is the Veggie Sandwich

Step-by-step explanation:

Given that there are four large submarine Sandwiches in a party and all of them are of the same size.

Some parts of each of them were eaten during the party. We are to find the Sandwich that has the least amount left.

The fractions of the Chicken Sandwich(C), Tuna Sandwich(T), Roast beef Sandwich(R) and the Veggie Sandwich(V) that were eaten during the party are given by

Therefore, the fractions of the Sandwiches that left will be

Out of the four fractions, V' is the smallest, so the Veggie Sandwich has the least amount left.

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A man and a woman agree to meet at a cafe about noon. If the man arrives at a time uniformly distributed between 11:40 and 12:10
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0.3888

Step-by-step explanation:

To solve the exercise we need a neutral time, so we define at 12:00 as time 0.

If the man arrives in a uniformly distributed time between 11:40 and 12:10, the time is distributed from -20 to 10.

If the woman arrives in a time evenly distributed between 11:45 and 12:20, the time is distributed from -15 to 20.

Assuming that each one arrives at 12: X and 12: Y for men and women, then the space of our time is defined as

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So,

f_x(x)=\frac{1}{10-(-20)}=\frac{1}{30}\\f_y(y)=\frac{1}{20-(-15)}=\frac{1}{35}

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The probability of finding an arrival less than 5 minutes is

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6 0
3 years ago
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