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polet [3.4K]
3 years ago
15

What is 76 to the 3rd power

Mathematics
2 answers:
ivann1987 [24]3 years ago
7 0
438976 !!
hope this helped
marishachu [46]3 years ago
6 0

Answer:

438976

Step-by-step explanation:

76^3

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When constructing parallel lines , how can you verify the lines constructed are parallel
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Answer:

  compare the distance between the lines at one point to the distance between the lines at another point

Step-by-step explanation:

You can construct perpendiculars at different points and compare the distance between the lines at those perpendiculars. The distance between parallel lines is the same everywhere.

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Simplify x + (7+14x)​
Brilliant_brown [7]

Answer:

15x + 7

Step-by-step explanation:

x + (7 + 14x)

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The pair of square pyramids are similar. Use the given information to find the scale factor of the smaller square pyramid to the
Mrrafil [7]
\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array}\\\\
-----------------------------

\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\
\stackrel{\stackrel{pyramids}{scale~factor}}{\cfrac{small}{large}}\qquad \qquad \cfrac{s}{s}=\cfrac{\sqrt[3]{64}}{\sqrt[3]{343}}\implies \cfrac{s}{s}=\cfrac{4}{7}\implies 4:7
8 0
3 years ago
I don't understand help
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3 years ago
Gretchen has a set of blocks of heights 1, 2, and 4-centimeters. Imagine stacking the blocks one on top of the other to make a t
notsponge [240]

Answer:

t_{n}=t_{n-1}+t_{n-2} +t_{n-4}

Step-by-step explanation:

t_{n}=multiple ways to climb a tower

When n = 1,

tower= 1 cm  

t_{1}= 1

When n = 2,

tower =2 cm   

t_{2}= 2

When n = 3,

tower = 3 cm

it can be build if we use three 1 cm blocks

t_{3} = 3

When n = 4,

tower= 4 cm

it can be build if we use four 1 cm blocks

t_{4} = 6

When n > 5

tower height > 4 cm

so we can use 1 cm, 2 cm and 4 cm blocks

so in that case if our last move is 1 cm block then t_{n-1} will be

n —1 cm

if our last move is 2 cm block then t_{n-2} will be

n —2 cm

if our last move is 4 cm block then t_{n-4} will be

n —4 cm

 

t_{n}=t_{n-1}+t_{n-2} +t_{n-4}

4 0
4 years ago
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