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topjm [15]
4 years ago
9

Evaluate if m equals 10 + n equals 12: n-m+2n÷12 can you please show me how you got this answer

Mathematics
1 answer:
Anna71 [15]4 years ago
7 0
Plug in m=10 n=12
12 - 10 + 2(12) + 12 \\ 12 - 10 + 24 + 12 \\ 2 + 24 + 12 \\ 26 + 12 \\  = 38
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What is the perimeter of the triangle?<br> O 22 units<br> O 30 units<br> O44 units<br> O 60 units
umka21 [38]

Answer:

22 units

Step-by-step explanation:

Add 12, 4 , and 6 and you will get 22

3 0
3 years ago
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What are the solutions of x^2+5x=2? Check all that apply
astraxan [27]
X^2+5x=2
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x=-5/2+-√33/2
3 0
3 years ago
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Select the postulate or theorem that you can use to conclude that the triangles are similar.
insens350 [35]

Answer: SAS similarity postulate

Step-by-step explanation:

According to SAS postulate of similarity, two triangles are called similar if two sides in one triangle are in the same proportion to the corresponding sides in the other, and the included angle are congruent.

In triangles, QNR and MNP,

\frac{QN}{MN} = \frac{QM+MN}{MN} = \frac{10+8}{8} = \frac{18}{8} = \frac{9}{4}

\frac{NR}{NP} = \frac{NP+NR}{NP} = \frac{10+8}{8} = \frac{18}{8} = \frac{9}{4}

\implies \frac{QN}{MN} = \frac{NR}{NP}

Also,

\angle QNR\cong \angle MNP  (Reflexive)

Thus, By SAS similarity postulate,

\triangle QNR\sim\triangle MNP

⇒ Option first is correct.

8 0
3 years ago
2) 4 6 2 3 If L= | 5 8 and M= 1 4 3 -2 -5 3 3 Find L-M -)) 2 4 8 A ) 3 4 5 2 3 B) 4 4 8 -5 6 9 o 6 12 -2 1 6 6 2 D) 9 12 1​
Misha Larkins [42]

\\ \sf\longmapsto L-M

  • Put values

\sf \left[\begin{array}{cc}\sf 4&\sf 6\\ \sf 5 &\sf 8 \\ \sf 3 &\sf -2\end{array}\right]-\left[\begin{array}{cc}\sf 2&\sf 3\\ \sf 1 &\sf 4 \\ \sf -5&\sf3\end{array}\right]

Just substract corresponding terms

\\ \sf\longmapsto \left[\begin{array}{cc}\sf 2 &\sf 3\\ \sf 4&\sf4\\ \sf 8&\sf -5\end{array}\right]

Option B

6 0
3 years ago
The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasin
hoa [83]

Answer:

\frac{dI}{dt}=-0.00016 A/s

Step-by-step explanation:

We are given that

By ohm's law

V=IR

R=389 ohm

I=0.03 A

\frac{dV}{dt}=-0.06V/s

\frac{dR}{dt}=0.07ohm/s

We have to find rate of change of current I means \frac{dI}{dt}

Differentiate the equation w.r.t t

\frac{dV}{dt}=\frac{dI}{dt}R+I\frac{dR}{dt}

Substitute the values then we get

-0.06=\frac{dI}{dt}\times 389+0.03\times 0.07

-0.06=389\frac{dI}{dt}+0.0021

-0.06-0.0021=389\frac{dI}{dt}

-0.0621=389\frac{dI}{dt}

\frac{dI}{dt}=\frac{-0.0621}{389}=-0.000160 A/s

Hence, the current I is changing at the rate=-0.00016A/s

4 0
4 years ago
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