3-y/2 =1. Help please
2 answers:
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Given:
A solution of 60% fertilizer is to be mixed with a solution of 21% fertilizer to form 234 liters of a 43% solution.
To find:
The quantity of the 60% solution in the mixture.
Solution:
Let x be the quantity of the 60% solution and y be the quantity of the 21% solution.
Quantity of mixture is 234. So,
...(i)
The mixture has 43% fertilizer. So,
Multiply both sides by 100.
...(ii)
Using (i) and (ii), we get
Divide both sides by -39.
Putting this value in (i), we get
Therefore, 132 liters of the 60% solution must be used.