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patriot [66]
2 years ago
12

HELP ME PLEASE DONT MIND THAT ANSWER DIDNT MEAN THE CLICK IT :(

Mathematics
1 answer:
yaroslaw [1]2 years ago
6 0

Answer:

B)240 sm

Step-by-step explanation

6*4=24 sm

24*10=240 sm

So that means the surface area of that rectangular prism is 240 square meters

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40 packs of baseball cards for discounted price of 64 he sells 30 packs of baseball cards to A friend at cost much should he cha
Trava [24]
Answer: $48

Step by step:
1. 30 packs times 64 dollars is 1920
2. 1920 divided by 40 packs is 48
because if you pay 64 for 40 packs and your trying to figure out how much for 30 packs you will want to set it up like this:

\frac{40}{64}  \times  \frac{30}{x}
then you will use fishy method Google fish method in math if this doesn't help

5 0
3 years ago
The College Board SAT college entrance exam consists of three parts: math, writing and critical reading (The World Almanac 2012)
Wittaler [7]

Answer:

Yes, there is a difference between the population mean for the math scores and the population mean for the writing scores.

Test Statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1 .

Step-by-step explanation:

We are provided with the sample data showing the math and writing scores for a sample of twelve students who took the SAT ;

Let A = Math Scores ,B = Writing Scores  and D = difference between both

So, \mu_A = Population mean for the math scores

       \mu_B = Population mean for the writing scores

 Let \mu_D = Difference between the population mean for the math scores and the population mean for the writing scores.

            <em>  Null Hypothesis, </em>H_0<em> : </em>\mu_A = \mu_B<em>     or   </em>\mu_D<em> = 0 </em>

<em>      Alternate Hypothesis, </em>H_1<em> : </em>\mu_A \neq  \mu_B<em>      or   </em>\mu_D \neq<em> 0</em>

Hence, Test Statistics used here will be;

            \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1    where, Dbar = Bbar - Abar

                                                               s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}}

                                                               n = 12

Student        Math scores (A)          Writing scores (B)         D = B - A

     1                      540                            474                                   -66

     2                      432                           380                                    -52  

     3                      528                           463                                    -65

     4                       574                          612                                      38

     5                       448                          420                                    -28

     6                       502                          526                                    24

     7                       480                           430                                     -50

     8                       499                           459                                   -40

     9                       610                            615                                       5

     10                      572                           541                                      -31

     11                       390                           335                                     -55

     12                      593                           613                                       20  

Now Dbar = Bbar - Abar = 489 - 514 = -25

 Bbar = \frac{\sum B_i}{n} = \frac{474+380+463+612+420+526+430+459+615+541+335+613}{12}  = 489

 Abar =  \frac{\sum A_i}{n} = \frac{540+432+528+574+448+502+480+499+610+572+390+593}{12} = 514

 ∑D_i^{2} = 22600     and  s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}} = \sqrt{\frac{22600 - 12*(-25)^{2} }{12-1} } = 37.05

So, Test statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1

                            = \frac{-25 - 0}{\frac{37.05}{\sqrt{12} } } follows t_1_1   = -2.34

<em>Now at 5% level of significance our t table is giving critical values of -2.201 and 2.201 for two tail test. Since our test statistics doesn't fall between these two values as it is less than -2.201 so we have sufficient evidence to reject null hypothesis as our test statistics fall in the rejection region .</em>

Therefore, we conclude that there is a difference between the population mean for the math scores and the population mean for the writing scores.

8 0
3 years ago
A ladder is 74 inches tall. How tall is it in feet and inches?
vivado [14]

Answer:1 inch = 0.0833333 feet so 74 x 0.0833333 = 6.16667

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
List an Order Pair from each of the 4 quadrants and tell which quadrant each point is in.
dexar [7]
( 1 ,2)  is in first quadrant

(-1,2) is in second
(-1,-2) is in the third
( 1, -2) is in 4th quadrant
7 0
3 years ago
Read 2 more answers
S 8,000 a good estimate for the sum of 3,816 and 467?
Damm [24]

Answer:

it is  not a good estimate.

Step-by-step explanation:3816 can be rounded to 4000 and 467 can be rounded to 500. Adding 4000+500 gives 4500, which isn't near 8000.

i hoped this helped :)

<3

7 0
3 years ago
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