All categories

2 years ago

Hiiii help please ahh

Mathematics

2 answers:

Brilliant_brown [7]2 years ago

7 0

Answer:

Question 1 Answer : x^2 - 2y^2

Question 2 Answer: x^2 $\pi$ - 36 $\pi$

Flauer [41]2 years ago

3 0

The correct answer is -36

You might be interested in

Help please! This is for geometry! Question below!!

labwork [276]

<span>1.) Circumscribed angle 2.) Minor arc 3.) Central Angle 4.) Inscribed Angle 5.)Major Arc</span>

4 0

2 years ago

Need help on this, need help now D:

baherus [9]

Answer:

$\sqrt{34}$

Step-by-step explanation:

Calculate the distance using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = A(- 2, 5) and (x₂, y₂ ) = B(3, 8)

d = $\sqrt{(3+2)^2+(8-5)^2}$

= $\sqrt{5^2+3^2}$

= $\sqrt{25+9}$

= $\sqrt{34}$

5 0

3 years ago

HELPPP PLEASEEEEEEEEE

liubo4ka [24]

Y=4x+7

So 4 is the rate of change because if you solve for y, x is the rate of change

4 0

3 years ago

Read 2 more answers

1000 was invested at 5.5% interest, compounded annually. After sometime the amount had grown to 1550. How long was the money inv

scZoUnD [109]

compound interest equation for annually compounded

$A=P(1+r)^t$

A=final amount

P=principal

r=rate in decimal

t=time in years

given that

A=1550

P=1000

r=5.5%=0.055

find t

$1550=1000(1+0.055)^t$

divide both sides by 1000

$1.55=1.055^t$

take ln of both sides

$ln(1.55)=ln(1.055^t)$

use ln rule $ln(a^b)=b(ln(a))$

$ln(1.55)=t(ln(1.055))$

divide both sides by ln(1.055)

$\frac{ln(1.55)}{ln(1.055)}=t$

using a calculator, we get that t=8.18544 yrs

so about 8.2yrs

4 0

2 years ago

Given the linear programming problem, use the method of corners to determine where the minimum occurs and give the minimum value

algol [13]

Answer:

Minimum value of function $C=x+10y$ is 63 occurs at point (3,6).

Step-by-step explanation:

To minimize :

$C=x+10y$

Subject to constraints:

$x\leq 3---(1)\\y\leq 9---(2)\\x+y\geq 9----(3)\\x\geq 0\\y\geq 0$

Eq (1) is in blue in figure attached and region satisfying (1) is on left of blue line

Eq (2) is in green in figure attached and region satisfying (2) is below the green line

Considering $x+y\geq 9$ , corresponding coordinates point to draw line are (0,9) and (9,0).

Eq (3) makes line in orange in figure attached and region satisfying (3) is above the orange line

Feasible region is in triangle ABC with common points A(0,9), B(3,9) and C(3,6)

Now calculate the value of function to be minimized at each of these points.

$C=x+10y$

at A(0,9)

$C=0+10(9)\\C=90$

at B(3,9)

$C=3+10(9)\\C=93$

at C(3,6)

$C=3+10(6)\\C=63$

Minimum value of function $C=x+10y$ is 63 occurs at point C (3,6).

3 0

3 years ago