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SVETLANKA909090 [29]
3 years ago
14

Write the equation of the line that goes through the points (-3.5) and (6,-1)

Mathematics
1 answer:
Leokris [45]3 years ago
6 0
The equation would be y = -3/2x + 1/2
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1)Which of the ordered pairs is NOT a
Butoxors [25]

Answer:

a) {(3,3),(3,4),(4,5),(4,6)}

Step-by-step explanation:

Given

(a) to (d)

Required

Which is not a function

A relation is represented as:

\{(x_1,y_1),(x_1,y_1),(x_2,y_2),...............(x_0,y_0)\}

For the relation t be a relation, then:

x_i \ne x_jwhere i \ne j

This means that none of the x values must be related.

The first relation has 3 repeated as its value of . Hence, (a) is a relation

8 0
3 years ago
PLEASE ANSWER ALL I WILL GIVE BRAINLIEST
sineoko [7]
0,0 1,3 2,4 3,8 4,5 5,5 6,2 7,0 hope that helps
6 0
3 years ago
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Use the formula to evaluate the infinite series. Round to the nearest hundredth if necessary.
kotykmax [81]

Answer:

3/4

Step-by-step explanation:

a1 = (-1/3)^0 = 1

r = -1/3

Hence S = 1/(1+1/3) = 1/(4/3) = 3/4

6 0
3 years ago
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Pls help
KATRIN_1 [288]

Answer:

169.04 in² (nearest hundredth)

Step-by-step explanation:

Surface area of a cone = \pir² + \pirl

(where r = radius of the base and l = slant height)

Given slant height l = 10 and surface area = 188.5

Surface area  = \pir² + \pirl

188.5 = \pir² + 10\pir

\pir² + 10\pir - 188.5 = 0

r = \frac{-10\pi +\sqrt{(10\pi )^2-(4\times\pi \times-188.5)} }{2\pi } = 4.219621117...

Volume of a cone = (1/3)\pir²h

(where r = radius of the base and h = height)

We need to find an expression for h in terms of l using Pythagoras' Theorem a² + b² = c², where a = radius, b = height and c = slant height

r² + h² = l²

h² = l² - r²

h = √(l² - r²)

Therefore, substituting found expression for h:

volume of a cone = (1/3)\pir²√(l² - r²)

Given slant height l = 10 and r = 4.219621117...

volume = 169.0431969... = 169.04 in² (nearest hundredth)

5 0
3 years ago
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Which list shows the numbers in increasing order?
slavikrds [6]

Answer:

-7/13, -3/5, -5/8

Step-by-step explanation:

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3 years ago
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