To determine when Mya will have both lessons again on the same day, you will list the multiples of each number of days because to show every 4 or 6 days, you will count by 4's and 6's.
When you get to the first number that is the same, that will be the next time she will have both lessons again. This is called the least common multiple (LCM).
4, 8, 12, 16, 20, ...
6, 12, 18, 24
In 12 days she will have both lessons again.
30000 is the answer as it is ajove 20000 in comparison to rounding down
Answer:
a) 2/3
b) 1/3
Step-by-step explanation:
Let X be the random event that measures the time you will have to wait.
Since time is uniformly distributed between 10 and 10:30 in intervals of 1 minute
P(n < X ≤ n+1) = 1/30 for every minute n=0,1,...29.
a)
P( X > 10) = 1 - P(X ≤ 10) = 1 - 10/30 = 2/3
b)
P(10 < X ≤ 20) = (20-10)/30 = 1/3
Answer:
78.45
Step-by-step explanation:
u know 3 as decimal is 0.03 so u multiply 2,615*0.03 which is 78.45
