Given the figure of a regular pyramid
The base of the pyramid is a hexagon with a side length = 6
The lateral area is 6 times the area of one of the side triangles
So, the side triangle has a base = 6
The height will be:
![\begin{gathered} h^2=6^2+(\frac{\sqrt[]{3}}{2}\cdot6)^2=36+27=63 \\ h=\sqrt[]{63} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%5E2%3D6%5E2%2B%28%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%5Ccdot6%29%5E2%3D36%2B27%3D63%20%5C%5C%20h%3D%5Csqrt%5B%5D%7B63%7D%20%5Cend%7Bgathered%7D)
so, the lateral area =
![6\cdot\frac{1}{2}\cdot6\cdot\sqrt[]{63}=18\sqrt[]{63}](https://tex.z-dn.net/?f=6%5Ccdot%5Cfrac%7B1%7D%7B2%7D%5Ccdot6%5Ccdot%5Csqrt%5B%5D%7B63%7D%3D18%5Csqrt%5B%5D%7B63%7D)
Answer:
A=950
B=540
Step-by-step explanation:
Answer:
P(A∪B) = 1/3
Step-by-step explanation:
Red Garments = 1 red shirt + 1 red hat + 1 red pairs of pants
Total Red Garments = 3
Green Garments = 1 green shirt + 1 green scarf + 1 green pairs of pants
Total Green Garments = 3
The total number of garments = Total Red Garments + Total Green Garments:
3 + 3 = 6
Let A be the event that he selects a green garment
P(A) = Number of required outcomes/Total number of possible outcomes
P(A) = 3/6
Let B be the event that he chooses a scarf
P(B) = 1/6
The objective here is to determine P(A or B) = P(A∪B)
Using the probability set notation theory:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∩B) = Probability that a green pair of pant is chosen = P(A) - P(B)
= 3/6-1/6
= 2/6
P(A∪B) = 1/2 + 1/6 - 2/6
P(A∪B) = 2/6
P(A∪B) = 1/3
Answer:
4, I went down first. It is coming by 1/2. Then I went up to 5 again..5=2 1/2. Then I went to 1/2 until I went to 8. 1/2 to 8 and got 4 total servings of milk
Step-by-step explanation:
