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is vector v with an initial point of (-5,22) and a terminal point of (20,60) equal to vector u with an intintal point of (50,120

marta [7]

Answer:

Yes, vectors u and v are equal.

Step-by-step explanation:

We need to check whether vectors u and v are equal or not.

If the initial point is $(x_1,y_1)$ and terminal point is $(x_2,y_2)$ , then the vector is

$Vector=(x_2-x_1)i+(y_2-y_1)j$

Vector v with an initial point of (-5,22) and a terminal point of (20,60).

$\overrightarrow v=(20-(-5))i+(60-22)j$

$\overrightarrow v=25i+38j$ ..... (1)

Vector u with an initial point of (50,120) and a terminal point of (75,158).

$\overrightarrow u=(75-50)i+(158-120)j$

$\overrightarrow u=25i+38j$ .... (2)

From (1) and (2) we get

$\overrightarrow u=\overrightarrow v$

Therefore, vectors u and v are equal.

5 0

3 years ago

Algebra quadrilateral dklm is a rhombus if dk=8, find kL

Luba_88 [7]

Pretty sure kL is also 8 since it’s a quadrilateral

4 0

2 years ago

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.

Romashka [77]

By definition, the average change of rate is given by:
$AVR = \frac{f(x2)-f(x1)}{x2-x1}$
We will calculate AVR for each of the functions.
We have then:

f(x) = x^2 + 3x interval: [-2, 3]:
$f(-2) = x^2 + 3x = (-2)^2 + 3(-2) = 4 - 6 = -2

f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18$
$AVR = \frac{-2-18}{-2-3}$
$AVR = \frac{-20}{-5}$
$AVR = 4$

f(x) = 3x - 8 interval: [4, 5]:
$f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7$
$AVR = \frac{7-4}{5-4}$
$AVR = \frac{3}{1}$
$AVR = 3$

f(x) = x^2 - 2x interval: [-3, 4]
$f(-3) = (-3)^2 - 2(-3) = 9 + 6 = 15

f(4) = (4)^2 - 2(4) = 16 - 8 = 8$
$AVR = \frac{8-15}{4+3}$
$AVR = \frac{-7}{7}$
$AVR = -1$

f(x) = x^2 - 5 interval: [-1, 1]
$f(-1) = (-1)^2 - 5 = 1 - 5 = -4

f(1) = (1)^2 - 5 = 1 - 5 = -4$
$AVR = \frac{-4+4}{1+1}$
$AVR = \frac{0}{2}$
$AVR = 0$

Answer:
these functions from the greatest to the least value based on the average rate of change are:
f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x

5 0

3 years ago

Write down the relation between mass and inerti

Leya [2.2K]

Answer:

The mass of an object is directly proportional to its inertia.

$m\alpha I$

Where

m = mass

I = inertia

Step-by-step explanation:

We can first of all start by defining the two key terms present here - mass and inertia.

The mass of an object is the quantity of matter contained in the object.

The inertia of an object is the resistance of an object which is in a state of rest to motion

The mass of an object is directly proportional to its inertia.

The heavier an object is, the more inertia it has. To put things into perspective, you can easily push a bicycle because it does not really have a lot of mass, as opposed to pushing an eighteen-wheeler trailer.

6 0

3 years ago

What is 7/12•3/2? Answer please

KengaRu [80]

Answer=7/8
7x3=21
12x2=24
21/24=7/8

6 0

3 years ago

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