Assuming that <span>4^2-6(2^x)-16=0 is correct, we can rearrange it as:
</span><span>-6(2^x) + 4^2 - 16=0
Are you sure it's not </span>6(2^x) + 4^2 - 16=0 ?
If 6(2^x) + 4^2 - 16=0 is correct, then
6(2^x) + 4^2 - 16=16 - 16 = 0, that is, 6(2^x) = 0. Then x = 0 (answer)
Answer:
Step-by-step explanation:
a1 = 6
a2 = 10
a3 = 14
The next member of the sequence is 4 more than the current sequence. Therefore d = 4
a1 = 6
d = 4
n = 13
an = a1 + (n - 1)*d
an = 6 + (n - 1)*4
a_13 = 6 + 12*4
a_13 = 6 + 48
a_13 = 54
Y=4x+4
I think this is it u just have to simplify to get it to y=mx+b
Hey DatGamer13!
Question:
Solve for x
Solution:
Subtract 10 from both sides.
3x^2 + 13x − 10 = 10 − 10
3x^2 + 13x − 10 = 0
Factor left side of equation.
(3x − 2) (x + 5) = 0
Set factors equal to 0.
3x − 2 = 0 or x + 5 = 0
Answer:
x = 2/3 or x = −5
