Answer:
A = 3E
A + E = 56
3E + E = 56
4E = 56
E = 14
Elga is 14 years old.
Step-by-step explanation:
Could you please mark me as the brainliest answer
For this problem plug in the given x and y values:
For the first one: No
second one: No
third one: Yes
fourth one: No
<h2>Answer :-</h2>
As we know that,
Pythagoras triplet
1) a² + b² = c²
Let
<h3>Hence, A can't be Pythagoras triplet</h3>
2) a² + b² = c²
<h3>Therefore, B can be Pythagoras triplet</h3>
3)a² + b² = c²
<h3>Hence, C can't be Pythagoras triplet</h3>
4) a² + b² = c²
<h3>Hence, D can't be Pythagoras triplet</h3>
<h2 /><h2>Therefore :-</h2>
Only B can be Pythagoras triplet.
Answer:
( , ) or x = y =
( 2.57 , 4.18) or x = 2.57 y = 4.18
Step-by-step explanation:
Use elimination:
Find the least common multiple between x or y in this case use -6 and 5 (make sure there are opposite signs)
11x - 6y = 2 multiply entire problem by 5
-8x + 5y = 3 multiply entire problem by 6
55x - 30y = 10 combine problems
<u>-48x + 30y = 18</u>
7x + 0y = 18
7x = 18 = Plug into one equation to find y
11() - 6y = 2
- 6y = 2
-6y = -
y=
Hope this helps :)
A=xy+yz
A=y*(x+z)
y=A/(x+z)