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anyanavicka [17]
3 years ago
15

2 1/4 miles in 1/4 hour

Mathematics
2 answers:
soldi70 [24.7K]3 years ago
7 0
9! i hope it helps you out!
vampirchik [111]3 years ago
5 0

Answer:

9

Step-by-step explanation:

Divide them.

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How many real roots does the equation (x^2+1)(x-2)=0 have?<br><br> A: 3<br> B: 1<br> C: 0<br> D: 2
seropon [69]
0 i think is the answer for
6 0
3 years ago
△XYZ is mapped to △X'Y'Z' using the rules (x, y)→(x+5, y−3) followed by (x, y)→(−x, −y) .
Yuri [45]

Given that △XYZ is mapped to △X'Y'Z' using the rules (x, y)→(x+5, y−3) followed by (x, y)→(−x, −y) .

We know that (x,y) => (x+h,y+k) type operation represents translation so rule (x, y)→(x+5, y−3)  will cause translation.

We know that (x,y) => (-x,-y) type operation represents rotation about origin so rule (x, y)→(−x, −y) will cause rotation.

So combining both results and comparing with given choices. we find that only 1st choice "△XYZ is congruent to △X'Y'Z' because the rules represent a translation followed by a rotation, which is a sequence of rigid motions."

is correct.

5 0
3 years ago
Really Important!!! Plz help!!! Will make you the brainliest!! Mia creates a box plot using 28, 34, 40, 24, 44, 49, and 32 as th
insens350 [35]
The correct box plot will have the "whiskers" extending to 24 and 49. The first quartile will be around 28.5 and the third quartile will be around 41.8. The median will be at 34. 

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3 0
4 years ago
HELPP FAST IS IT RIGHT
dexar [7]

Answer:

Yes it is

Step-by-step explanation:

8 0
3 years ago
The product of two integers is eighty,their quotient is five.Write both integers in numerical order and separated by a comma,no
Goryan [66]

SOLUTION

Let the two integers be x and y.

Now, the product of x and y, is 80, that is

\begin{gathered} x\times y=80 \\ xy=80\ldots\ldots\text{.equation 1} \end{gathered}

The quotient of x and y is 5, that is

\begin{gathered} x\div y=5 \\ \frac{x}{y}=5\ldots\ldots\ldots\ldots\text{.}\mathrm{}\text{equation 2} \end{gathered}

From equation 2, make x, the subject, we have

\begin{gathered} \frac{x}{y}=5 \\ \text{cross multiplying } \\ 5\times y=x \\ x=5y \end{gathered}

Now substitute the x for 5y into equation 1, we have

\begin{gathered} xy=80 \\ 5y\times y=80 \\ 5y^2=80 \\ \text{dividing by 5} \\ y^2=\frac{80}{5} \\ y^2=16 \\ \text{take square root of both sides } \\ \sqrt[]{y^2}=\sqrt[]{16} \\ \text{square cancels root} \\ y=4 \end{gathered}

Now substitute y for 4 into any of the equations.

Let us use equation 1 again, we have

\begin{gathered} xy=80 \\ x\times4=80 \\ 4x=80 \\ x=\frac{80}{4} \\ x=20 \end{gathered}

Hence the answer is 4, 20

4 0
1 year ago
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