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9966 [12]
2 years ago
9

Does anyone know how to do this?? thank you for your help

Mathematics
1 answer:
sweet [91]2 years ago
8 0

Answer:

substitute 1 for t

Step-by-step explanation:

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\lim\limits_{x\to\pm\infty}\dfrac{x^2+7x+12}{-x^2-3x+4}=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(1+\dfrac{7}{x}+\dfrac{12}{x^2}\right)}{x^2\left(-1-\dfrac{3}{x}+\dfrac{4}{x^2}\right)}=\dfrac{1}{-1}=-1\\\\\boxed{y=-1}

6 0
3 years ago
What is the answer please?
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