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9966 [12]
2 years ago
9

Does anyone know how to do this?? thank you for your help

Mathematics
1 answer:
sweet [91]2 years ago
8 0

Answer:

substitute 1 for t

Step-by-step explanation:

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An accounting professor wants to know the average GPA of the students enrolled in her class. She looks up information on Blackbo
olya-2409 [2.1K]

Answer:

a) True

b) Parameter

Step-by-step explanation:

We are given the following in the question:

An accounting professor wants to know the average GPA of the students enrolled in her class.

Population:

  • It is defined as the collection of all variables of interest.
  • A sample of individuals of interest is drawn from a population.

For the given case

Individuals of interest:

Students enrolled in accounting class

Population of interest:

Students enrolled in accounting class

Characteristic of interest:

Average GPA of the students enrolled in her class.

a) The population is all students enrolled in the accounting class.

The given statement is true as it contains all the observation of all the individuals of interest.

b) The computed average GPA of all the students enrolled in the class is 3.29

Statistic is a descriptive measure that describes a sample where as a parameter is a measure that describes the population.

Since 3.29 is the average of all the students enrolled in her class that is the average GPA of population.

Thus, 3.29 is a parameter.

6 0
4 years ago
What is 1 20/32 as a decimal and percent?
Lynna [10]
1 \frac{20}{32}= \frac{52}{32}= 1,.625 -\ decimal \\ \\ p\% \ of \ \frac{52}{32}= \frac{p}{100}*\frac{52}{32}= \\ \\\ p=\frac{100*52}{32} \\ \\ \boxed{p=162,5}
3 0
3 years ago
Pls help!!!!!!!!!!!!!!!!
Helga [31]

Answer:

m1=120

m2=120

m3=120

m4=60

m1=56

m2=56

m3=56

m4=124

6 0
3 years ago
In a survey, 75% of people
liubo4ka [24]

Answer:

67%

Step-by-step explanation:

24/75%= 33

100-33= 67

3 0
3 years ago
Please help will give brainlist!​
Yuki888 [10]

Answer:

b=\frac{1}{6}

Step-by-step explanation:

In f(x)=a\cos(b(x-c))+d, b represents a constant related to the period of the function. Here's how it's related:

b=\frac{2\pi}{T}, where T is the period of the function.

We're given T=12\pi, so solving for b:

b=\frac{2\pi}{12\pi}=\boxed{\frac{1}{6}}

4 0
3 years ago
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