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3 years ago

Which is the simplified expression for questions 1 2 3 4? (Look at photo)

Mathematics

1 answer:

Anit [1.1K]3 years ago

6 0

1. 9.5x + 1.5
2. 9x + 36
3. 4.8x + 2
4. 22x + 2

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Which line has the smallest slope? y= 3x v=9x y= .4x y= .25x

pentagon [3]

Y=.25x is the answer

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4 years ago

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What is the average rate of change of the function over the interval x = 0 to x = 5?

AURORKA [14]

$\bf slope = m = \cfrac{rise}{run} \implies \cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby \begin{array}{llll} average~rate\\ of~change \end{array}\\\\[-0.35em] \rule{34em}{0.25pt}\\\\ f(x)= 2x^2-1\qquad \begin{cases} x_1=0\\ x_2=5 \end{cases}\implies \cfrac{f(5)-f(0)}{5-0} \\\\\\ \cfrac{[2(5)^2-1]~~-~~[2(0)^2-1]}{5}\implies \cfrac{50-(-1)}{5}\implies \cfrac{50+1}{5}\implies \cfrac{51}{5}\implies 10\frac{1}{5}$

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3 years ago

Could someone break it down. I am not catching on.

sleet_krkn [62]

$\bf -0.04y+0.11(9000-y)=0.35y
\\\\\\
-0.04y+990-0.11y=0.35y
\\\\\\
990-0.15y=0.35y\implies 990=0.35y+0.15y
\\\\\\
990=0.50y
\implies 
\cfrac{990}{0.5}=y\implies 1980=y$

6 0

4 years ago

According to data from a medical association, the rate of change in the number of hospital outpatient visits, in millions, in

GaryK [48]

Answer:

a) $f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000$

b) f(t=2015) = 264,034,317.7

Step-by-step explanation:

The rate of change in the number of hospital outpatient visits, in millions, is given by:

$f'(t)=0.001155t(t-1980)^{0.5}$

a) To find the function f(t) you integrate f(t):

$\int \frac{df(t)}{dt}dt=f(t)=\int [0.001155t(t-1980)^{0.5}]dt$

To solve the integral you use:

$\int udv=uv-\int vdu\\\\u=t\\\\du=dt\\\\dv=(t-1980)^{1/2}dt\\\\v=\frac{2}{3}(t-1980)^{3/2}$

Next, you replace in the integral:

$\int t(t-1980)^{1/2}=t(\frac{2}{3}(t-1980)^{3/2})- \frac{2}{3}\int(t-1980)^{3/2}dt\\\\= \frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}+C$

Then, the function f(t) is:

$f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+C'$

The value of C' is deduced by the information of the exercise. For t=0 there were 264,034,000 outpatient visits.

Hence C' = 264,034,000

The function is:

$f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000$

b) For t = 2015 you have:

$f(t=2015)=0.001155[\frac{2}{3}(2015)(2015-1980)^{1/2}-\frac{4}{15}(2015-1980)^{5/2}]+264,034,000\\\\f(t=2015)=264,034,317.7$

3 0

3 years ago

PLS HELP ME ILL GIVE YOU BRAINIEST!!!

kenny6666 [7]

The total surface area of the three figures are 702 square feet.

<h3>How to estimate the amount of metal needed to produce a given amount of figures</h3>

According to this problem, we are required to determine the amount of metal needed to build three pieces with the dimensions presented in the figure.

In this case, we need to estimate the total surface area ( $A_{T}$ ), in square feet, required for the production of the three pieces, that is, the product of the number of pieces (n), no unit, and the surface area of each piece (A).

Now we proceed to calculate the total surface area:

$A_{T} = n\cdot A$

$A_{T} = 3\cdot \left[(5\,ft)\cdot (8\,ft) + (2\,ft)\cdot (8\,ft)+(8\,ft)\cdot (7\,ft)+(3\,ft)\cdot (8\,ft) \\$

$+(5\,ft)\cdot (8\,ft)+2\cdot (3\,ft)\cdot (5\,ft) + 2\cdot (4\,ft)\cdot (2\,ft) + (3\,ft)\cdot (4\,ft) ]$

$A_{T} = 702\,ft^{2}$

The total surface area of the three figures are 702 square feet. $\blacksquare$

To learn more on surface areas, we kindly invite to check this verified question: brainly.com/question/2835293

7 0

2 years ago

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