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IgorC [24]
3 years ago
11

3. Find the measure of side DF. See image below.

Mathematics
1 answer:
ad-work [718]3 years ago
4 0

Answer:

d. 5.25

Step-by-step explanation:

make it into two fractions: 6/8 = x/7

solve for x by cross multiplying.

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Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.
charle [14.2K]

ANSWER

See below

EXPLANATION

Given

f(x) =  \frac{ {x}- 9 }{x + 5}

and

g(x) =   \frac{ - 5x - 9}{x - 1}

(f \circ \: g)(x)=  \frac{ (\frac{ - 5x - 9}{x - 1})- 9 }{(\frac{ - 5x - 9}{x - 1} )+ 5}

(f \circ \: g)(x)=  \frac{ \frac{ - 5x - 9 - 9(x - 1)}{x - 1}}{\frac{ - 5x - 9 + 5(x - 1)}{x - 1} }

Expand:

(f \circ \: g)(x)=  \frac{ \frac{ - 5x - 9 - 9x  + 9}{x - 1}}{\frac{ - 5x - 9 + 5x - 5}{x - 1} }

(f \circ \: g)(x)=  \frac{ \frac{ - 5x - 9x  + 9 - 9}{x - 1}}{\frac{ - 5x + 5x - 5 - 9}{x - 1} }

(f \circ \: g)(x)=  \frac{ \frac{ - 14x }{x - 1}}{\frac{ -14}{x - 1} }

Since the denominators are the same, they will cancel out,

(f \circ \: g)(x)= \frac{ - 14x}{ - 14}  = x

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Answer:

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Step-by-step explanation:

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