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3 years ago

a paper factory makes 8415 sheets of paper and 45 minutes how many sheets of paper does the factory make in one minute

Mathematics

2 answers:

insens350 [35]3 years ago

5 0

187 divide the numbers and you will get your answer

lesantik [10]3 years ago

4 0

Do 8415 divided by 45 which is 187

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Goal is to make $100. What % of the goal was met if raised $350?

slega [8]

______________________________

<h3>A = m ÷ t × 100</h3><h3>= $100 ÷ $350 × 100</h3><h3>= <u>28.6%</u></h3><h3>THE GOAL WAS SURPASSED BY 28.6%</h3>

______________________________

7 0

3 years ago

Answer this quick I have 20 minutes<br> 25 points

e-lub [12.9K]

The answer is A. You can comment if u want an explanation :)

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2 years ago

What are the next 5 numbers on the following sequence 0, 3, 8, 15, 24

son4ous [18]

Answer:

35, 48 63 80 99

Step-by-step explanation:

please mark me as brainlest

6 0

1 year ago

Read 2 more answers

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

3 years ago

Mary who is 13 years old wants to have $8500 to travel to Argentina when she’s 21 years old. She currently has $6439 in savings

marishachu [46]

Answer:

a; she will have $8812

b: It will be enough for her trip

Step-by-step explanation:

In this question, we are tasked with calculating how much a certain value in a savings account that is earning an interest that is compounded annually will be worth.

To calculate this, we use the compound interest formula;

A = P( $(1+r/n)^{nt}$

Where A is the amount after that number of years which of course we want to calculate

P is the principal amount which is the amount we are investing which is $6439 according to the question

r is the interest rate which is 4% = 4/100 = 0.04

t is the time which is 8 years

n is 1 which is the number of times interest will be compounded annually

We plug these values as follows;

A = 6439(1 + 0.04/1)^8

A = 6439(1.04)^8

A = $8,812.22

This amount is greater then the needed $8,500 for the trip and of course it will be enough

8 0

3 years ago