Answer:
3lny - ln7
Step-by-step explanation:
We need to look at two properties that can determine our answer, first off is the obvious rule of subtraction between two logs, when subtracted, the numbers on the right of the log must be divided together.
The other one is the y^3, which means that we need to look for a logarithm that has 3 in the front of it because when a number in front of a logarithm exists, it must turn into an exponent of the number of the right of the logarithm.
With this, we can cross out the ones without the 3 in front, which would be D. lny - ln7 + 3
Now, we see that y is the one with the exponent, meaning that the equation with the 3 in front of the logarithm of y is correct, cross out the ones without, which is A. 3ln7 - ln7
Now when subtracting, the first logarithm will be the numerator while the second logarithm will be the denominator. Leaving us with our final answer being C. 3lny - ln7
(y^3 [3lny] / 7 [ln7])
Answer/Step-by-step explanation:
Let x hours be the number of hours Issac worked
x+6 hours be the number of hours Ruby worked
4(x+6) hours be the number of hours Svetlana worked.
x + x + 6 + 4(x+6) = 126
x + x + 6 + 4x +24 = 126
6x +30 = 126
6x = 96
x = 16
Therefore, Issac worked 16 hours.
Ruby worked 16+6 = 22 hours
Svetlana worked 22 × 4 = 88 hours.
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F(10)=300+35(10)
f(10)=300+350
650(10)=300+350
6500
The test statistic is -0.46 and the p-value is gotten as 0.3340
<h3>How to Calculate the P-value?</h3>
The question is not complete because the data from the sample is 105, 107, 117, 106, 110.
Mean of sample is;
Mean = (105 + 107 + 117 + 106 + 110)/5
Mean; x' = 109
From online standard deviation calculator, the standard deviation of the sample is; S = 4.848
Now, the claim is that your team scored an average significantly less than 110 points. Thus, let's define the hypothesis as;
Null Hypothesis; μ = 110
Alternative Hypothesis; μ < 110
standard error of the mean; S_m = S/√n
S_m = 4.848/5
S_m = 2.17
Thus, the t-statistic is;
t = (x' - μ)/S_m
t = (109 - 110)/2.17
t = -0.46
Degree of freedom for this sample size is;
D.F = N - 1 =5 - 1 = 4
From online p-value from t-score calculator, we have;
p-value = 0.3340
The p-value is greater than the significance value and as such we fail to reject the null hypothesis and conclude that there is not enough evidence to support the claim that your team scored an average significantly less than 110 points.
Read more about p-value at; brainly.com/question/4621112
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