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MakcuM [25]
3 years ago
15

Consider the two points B(-2, -3) and C(4,2).

Mathematics
1 answer:
postnew [5]3 years ago
3 0

Answer:

distance between B and C

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(1) [6pts] Let R be the relation {(0, 1), (1, 1), (1, 2), (2, 0), (2, 2), (3, 0)} defined on the set {0, 1, 2, 3}. Find the foll
goldenfox [79]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

In point 1:

The Reflexive closure:  

Relationship R reflexive closure becomes achieved with both the addition(a,a) to R Therefore, (a,a) is  (0,0),(1,1),(2,2) \ and \ (3,3)

Thus, the reflexive closure: R={(0,0),(0,1),(1,1),(1,2),(2,0),(2,2),(3,0), (3,3)}

In point 2:

The Symmetric closure:

R relation symmetrically closes by adding(b,a) to R for each (a,b) of R  Therefore, here (b,a) is:   (0,1),(0,2)\ and \ (0,3)

Thus, the Symmetrical closure:

R={(0,1),(0,2),(0,3)(1,0),(1,1)(1,2),(2,0),(2,2),(3,0), (3,3)}

8 0
2 years ago
NEED HELP PLZ!!!!!!!!!!!!!
podryga [215]

Answer:

1st Option is correct

Step-by-step explanation:

Just keep adding 150 to see the results

8 0
2 years ago
0.75x - y = - 2.1<br> 0.6y 2.4x +9
Alex17521 [72]

Answer:

4x-3

Step-by-step explanation:

Yea

6 0
3 years ago
1. What is the difference between the altitude rule and the leg rule?
Anna71 [15]

Answer:

The altitude to the hypotenuse of a right triangle forms two triangles that are similar to each other and to the original triangle

The Leg Rule (or Leg geometric mean theorem) relates the length of each leg of a right triangle with the segments projected by them on the hypotenuse.

Step-by-step explanation:

The altitude to the hypotenuse of a right triangle is the mean proportional between the segments into which it divides the hypotenuse. Notice the triangle used with this rule. The leg of a right triangle is the mean proportional between the hypotenuse and the projection of the leg on the hypotenuse.

6 0
2 years ago
Solve the following equation by factoring: x^2+ x– 42 = 0
Anastaziya [24]

Answer:

x=6,x=-7

Step-by-step explanation:

x^2+x-42=0

x^2-6x+7x-42=0

x(x-6)7(x-6)=0

(x-6)(x+7)=0

3 0
2 years ago
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