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3 years ago

Simplify the radical

Mathematics

1 answer:

prisoha [69]3 years ago

6 0

Answer:

2 sqrt 6n/3n^2

Step-by-step explanation:

expand, multiply the fractions, calculate, multiply, calculate

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Find the volume of a cone with a base radius of 6 yd and a height of 9 yd

Veronika [31]

$\text {Volume =} \dfrac{1}{3} \pi r^{2} h$

$\text {Volume =} \dfrac{1}{3} \pi (6)^{2} (9)$

$\text {Volume =} 339.29 \ yd^3$

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3 years ago

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3 years ago

Which statement best explains whether △PQR is congruent to △XYZ?

slamgirl [31]

D. because PQR and XYZ are not congruent

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3 years ago

Square root3(square root3+2square root12) simplify it.Answer should be square root 3.

julsineya [31]

Answer:

sqrt3[sqrt3+2sqrt12]=sqrt3[sqrt3+4sqrt3] = sqrt3[5sqrt3= 3x5 =15

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3 years ago

Read 2 more answers

What is the product?

ZanzabumX [31]

Answer:

The product is:

$\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]$

Step-by-step explanation:

For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:

$\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]$

$1 \times 2 + 3 \times 3 + 1 \times -2 = 15$

So the value of the element in the position $a_{11}$ is 15

$1 \times -2 + 3 \times 5 + 1 \times 1 = 14$

So the value of the element in the position $a_{12}$ is 14

Then with these two values you can determinate the result matrix.

$\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]$

3 0

2 years ago