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mrs_skeptik [129]
2 years ago
13

What is the product?

Mathematics
1 answer:
ZanzabumX [31]2 years ago
3 0

Answer:

The product is:

\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]

Step-by-step explanation:

For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:

\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]

1 \times 2 + 3 \times 3 + 1 \times -2 = 15

So the value of the element in the position a_{11} is 15

1 \times -2 + 3 \times 5 + 1 \times 1 = 14

So the value of the element in the position a_{12} is 14

Then with these two values you can determinate the result matrix.

\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]

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A three-digit number ends in number 7. If you put the number 7 in the first position, the number will increase by 324. Find the
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Answer:

<u>The original three-digit number is 417</u>

Step-by-step explanation:

Let's find out the solution to this problem, this way:

x = the two digits that are not 7

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The value of the shifted number = 700 + x

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Therefore, we have:

324 = (700 + x) - (10x + 7)

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Step-by-step explanation:

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<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

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Step-by-step explanation:

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