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2 years ago

If x = 2, y = -1, Simplify and find the value of x(2) - 3 (x(2) + y(2) - 4).

Mathematics

2 answers:

noname [10]2 years ago

5 0

Answer:

I think it would be -4x-6y+12

Maurinko [17]2 years ago

4 0

Answer:

Step-by-step explanation:

Plug in the values to "x" and "y" and solve.

Solve:

2(2) - 3(2(2) - 1(2) - 4)

2(2) - 3(4 - 1(2) - 4)

2(2) - 3(4 - 2 - 4)

2(2) - 3(-2)

4 - 3(-2)

4 + 6

Your answer would be 10.

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2 years ago

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2 years ago

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3 years ago

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3 years ago

A recent study asked U. S. Adults to name 10 historic events that occurred during their lifetime that have had the greatest impa

Nadusha1986 [10]

Using the z-distribution, as we are working with a proportion, it is found that the 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, the parameters are:

$z = 2.575, n = 2000, \pi = 0.77$

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 - 2.575\sqrt{\frac{0.77(0.23)}{2000}} = 0.7458$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 + 2.575\sqrt{\frac{0.77(0.23)}{2000}} = 0.7942$

The 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.

More can be learned about the z-distribution at brainly.com/question/25890103

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2 years ago