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2 years ago

The side length of an equilateral triangle is 6x - 12. Write an expression for the perimeter of the triangle in simplest form.

Mathematics

1 answer:

kirill [66]2 years ago

4 0

Answer:

18x - 36

Step-by-step explanation:

In an equilateral triangle the 3 sides are congruent, then

perimeter = 6x - 12 + 6x - 12 + 6x - 12 ← collect like terms

= 18x - 36

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" If $6000 is borrowed at 7.5% simple interest for 2 yr, then the amount of interest is "

Mnenie [13.5K]

Answer:

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3 years ago

119. Beatrice decides to deposit $100 per month at the end of every month in a bank with an annual interest rate of 5.5% compoun

sveta [45]

Answer:

Beatrice will accumulate $1230.72 at the end of the year.

Step-by-step explanation:

We can write:

$(1+\frac{0.055}{12})=z$

$100=C$ for deposits

The first month would have only the deposit reflected in her balance, then, expanding some steps of the calculation would yield:

$S_{1}=C\\S_{2}=Cz + C\\S_{3}=Cz^{2}+Cz + C\\S_{n}=Cz^{n-1} +...+Cz+C$

A geometric series is given by:

$1+x+...+x^{m}=\frac{x^{m+1}-1}{x-1}$

Translating our series to the short form:

$S_{n}=C(\frac{z^{n}-1}{z-1} )$

plugin in the values for the 12 month gives:

$S_{12}=100(\frac{(1+\frac{0.055}{12})^{12} -1}{\frac{0.055}{12}})=1230.7169$

3 0

3 years ago

What power of 10 makes this expression equal to 30,000? 3 x 10

pickupchik [31]

Answer:

10x3000

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

I need help!!!!!!!!!!!!!!!!

SVETLANKA909090 [29]

Y=-3 is your answer

6 0

3 years ago

Suppose that an airline overbooks seats on their flights. In particular, it sells 300 tickets for a flight when there are only 2

vladimir1956 [14]

Using the normal approximation to the binomial, it is found that there is a 0.994 = 99.4% probability that we will have enough seats for everyone who shows up.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with $\mu = np, \sigma = \sqrt{np(1-p)}$ .

In this problem:

15% do not show up, so 100 - 15 = 85% show up, which means that $p = 0.85$ .
300 tickets are sold, hence $n = 300$ .

The mean and the standard deviation are given by:

$\mu = np = 300(0.85) = 255$

$\sigma = \sqrt{np(1-p)} = \sqrt{300(0.85)(0.15)} = 6.185$

The probability that we will have enough seats for everyone who shows up is the probability of at most 270 people showing up, which, using continuity correction, is $P(X \leq 270 + 0.5) = P(X \leq 270.5)$ , which is the p-value of Z when X = 270.5.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{270.5 - 255}{6.185}$

$Z = 2.51$

$Z = 2.51$ has a p-value of 0.994.

0.994 = 99.4% probability that we will have enough seats for everyone who shows up.

A similar problem is given at brainly.com/question/24261244

8 0

3 years ago