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Lady bird [3.3K]
3 years ago
15

Anybody know the answer?

Mathematics
1 answer:
-BARSIC- [3]3 years ago
6 0
No I am sorry
Try to surf the slope rise over run it might help
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Alona [7]

I believe the answer is BC, AB, AC

6 0
3 years ago
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What is the solution to log2(2x^3 - 8) - 2log2x = log2x?
Natalka [10]
The answer to the problem is x=2
7 0
3 years ago
Find area of a parallelogram with a height of 8 inches and a base of 14 inches
12345 [234]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{112 \:  {inches} \: ^{2} }}}}}

Step-by-step explanation:

Given,

Height of a parallelogram ( h ) = 8 inches

Base of a parallelogram ( b ) = 14 inches

Area of a parallelogram ( A ) = ?

<u>Finding </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>parallelogram</u>

<u>\boxed{ \sf{area \: of \: parallelogram \:  =  \: base \:  \times  \: height}}</u>

⇒<u>\sf{area \: of \: parallelogram \:  =  \: 14  \: \times 8}</u>

⇒<u>\sf{area \: of \: parallelogram = 112 \:  {inches}^{2} }</u>

Hope I helped!

Best regards! :D

4 0
3 years ago
The half-life of radium-226 is 1600 years. Suppose we have a 27-mg sample.
slega [8]

A function m(t)= m₀e^(-rt) that models the mass remaining after t years is; m(t) = 27e^(-0.00043t)

The amount of sample that will remain after 4000 years is; 4.8357 mg

The number of years that it will take for only 17 mg of the sample to remain is;  1076 years

<h3>How to solve exponential decay function?</h3>

A) Using the model for radioactive decay;

m(t)= m₀e^(-rt)

where;

m₀ is initial mass

r is rate of growth

t is time

Thus, we are given;

m₀ = 27 mg

r = (In 2)/1600 = -0.00043 which shows a decrease by 0.00043

and so we have;

m(t) = 27e^(-0.00043t)

c) The amount that will remain after 4000 years is;

m(4000) = 27e^(-0.00043 * 4000)

m(4000) = 27 * 0.1791

m(4000) = 4.8357 mg

d) For 17 mg to remain;

17 = 27e^(-0.00043 * t)

17/27 = e^(-0.00043 * t)

In(17/27) = -0.00043 * t

-0.4626/-0.00043 = t

t = 1076 years

Read more about Exponential decay function at; brainly.com/question/27822382

#SPJ1

5 0
1 year ago
Which sum or difference is modeled by the algebra tiles? A. (x2 4x − 2) (x2 − 2x − 4) = 2x2 2x 2 B. (x2 4x − 2) (x2 2x 4) = 2x2
dimulka [17.4K]

Answer:

Because (-x²+2x+3)+(-x²-2x-1) = -x²+2x+3-x²-2x-1 = -2x²+2

Step-by-step explanation:

Hope It Helps!

5 0
2 years ago
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