Number line graph with closed circle on 30 and shading to the rightbecause you already have 30 dollars and they need at least 120 but if they get more then 120 they can still hold the science fair.
Answer:
Selling price of the first pipe = $1.20
Profit = 20%
Let’s try to find the cost price of the first pipe
CP = Selling price - Profit
CP = 1.20 - 20% of CP
CP = 1.20 - 0.20CP
CP + 0.20CP = 1.20
1.20CP = 1.20
CP = 1.201.20
CP = $ 1
Selling price of the Second pipe = $1.20
Loss = 20%
Let’s try to find the cost price of the second pipe
CP = Selling price + Loss
CP = 1.20 + 20% of CP
CP = 1.20 + 0.20CP
CP - 0.20CP = 1.20
0.80CP = 1.20
CP = 1.200.80
CP = $1.50
Therefore, total cost price of the two pipes = $1.00 + $1.50 = $2.50
And total selling price of the two pipes = $1.20 + $1.20 = $2.40
Loss = $2.50 – $2.40 = $0.10
Therefore, Mr. Jones loss 10 cents.
i know that this is hard to understand so tell me if you need help
Have a great day :)
Answer:
The probability of drawing three red marbles is 1/27, or about 3.71%
Step-by-step explanation:
Add all the marbles:
5 + 4 + 6 = 15
Find favourable outcomes:
5
The probability for drawing a red marble is:
5/15 or 1/3
Multiply this ×3 to find the probability of drawing three red marbles.
1/3 × 1/3 × 1/3 = 1/27
1 ÷ 27 = 0.0370370370 ... repeating
An equation because of the equal sign
Answer:
the inflection points are
So,
It is concave down at the intervals
![(-\infty , -0.85] \cup [-0.14,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%20%2C%20-0.85%5D%20%5Ccup%20%5B-0.14%2C%5Cinfty%29)
And it would be concave up at
Step-by-step explanation:
Remember that to find inflection points you need to find where
Since
Then using the product and the chain rule you have that
And then, using again the chain rule and the product rule you have that
Therefore you have to solve the equation
Using the quadratic equation you get that there are two solutions, so the inflection points are
So,
Now remember that a function is concave up if the derivative is greater than zero and concave down if the derivative is less than zero. Therefor you have to solve these inequalties
And you would get that is concave down at the intervals
And it would be concave up at
