Question

If s^2– 4s – 6 = 6, What are the possible values of s?

Answer 1

Answer:

s = +6 or -2

Step-by-step explanation:

${s}^{2} - 4s - 6 = 6$

$= > {s}^{2} - 4s - 6 - 6 = 0$

$= > {s}^{2} - 4s - 12 = 0$

Lets factorise the eqn.

$= > {s}^{2} - 6s + 2s - 12 = 0$

$= > s(s - 6) + 2(s - 6) = 0$

$= > (s - 6)(s + 2) = 0$

Here 's' will have 2 values.

1) $s - 6 = 0$

$= > s = 6$

2) $s + 2 = 0$

$= > s = - 2$