Answer:C 5000 feet
Step-by-step explanation:It’s slightly less then a mile.
The present age of Jane is 45 years old and present age of her sister is 9 years old
<em><u>Solution:</u></em>
Let the present age of Jane be "x"
Let the present age of her sister be "y"
<em><u>Jane is 5 times older than her sister</u></em>
present age of Jane = 5(present age of her sister)
x = 5y ---------- eqn 1
<em><u>In 3 years, Jane’s sister will be 1/4 her age</u></em>
Age of sister after 3 years = 3 + y
Age of jane after 3 years = 3 + x
Age of sister after 3 years = 1/4(age of jane after 3 years)

Substitute eqn 1 in above equation

Substitute y = 9 in eqn 1
x = 5(9)
x = 45
Thus present age of Jane is 45 years old and present age of her sister is 9 years old
0, 1/2, -53, and 0.433 all belong in rational category
Answer:
Monomial; Standard form: 18a^2b^2
Step-by-step explanation:

It seems like you've begun to apply the grouping method.
Because the two binomials in the parentheses are the same, we can rewrite this as
(5ab-4)(x+6)
(x+6) cannot be further factored. (5ab-4) cannot be further factored either.
Final answer: (5ab-4)(x+6)