2 years ago

A man is now 3 times as old as his son. In 10 years time, the sum of their ages will be 76.

Mathematics

1 answer:

mr Goodwill [35]2 years ago

4 0

Answer:

Step-by-step explanation:

A man is now 3 times as old as his son.

m = 3s

In 10 years time, the sum of their ages will be 76

(m + 10) + (s + 10) = 76

Subsitute for m = 3s

(3s + 10) + (s + 10) = 76

4s + 20 = 76

4s = 56

s = 14

m = 3s = 14 * 3

m = 42

------------------------

How old was the man when his son was born?

m - s = 42 - 14

m - s = 28

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