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laila [671]
3 years ago
8

3 points

Mathematics
1 answer:
Anastasy [175]3 years ago
7 0
If 3 points and pi is 3.14 that would have to be equal to 6t
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K12 math work need help MARK CROWN JUST NEED HELP
VladimirAG [237]

Answer:

60

Step-by-step explanation:

9 ÷ 15 = 0.6

Move decimal 2 places 0.6 -> 60

7 0
3 years ago
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Suppose that ,LV YM, YV = 11 cm, and ⊙L has a diameter of 26 cm. Find YM.
Inessa05 [86]

Answer: I just had this on a test the answer is [ 22cm ]

8 0
3 years ago
A factory received a shipment of 10 generators, and the vendor who sold the items knows there are 4 generators in the shipment t
jek_recluse [69]

Answer:

A) 0.026

B) 0.130

Step-by-step explanation:

Complete Question

A factory received a shipment of 10 generators and the vendor who sold the items knows there are 4 generators in the shipment that are defective. Before the receiving foreman accepts the delivery, he samples the shipment, and if too many of the generators in the sample are defective, he will refuse the shipment. Give answer as a decimal to three decimal places.

(A) If a sample of 4 generators is selected, find the probability that all in the sample are defective.

(B) If a sample of 4 generators is selected, find the probability that none in the sample is defective.

Solution

A) This is a binomial distribution problem

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = number of generators to be picked = 4

x = Number of successes required = number of defective generators required = 4

p = probability of success = probability that a randomly selected generator is defective = (4/10) = 0.40

q = probability of failure = probability that a randomly selected generator is NOT defective = 1 - p = 1 - 0.40 = 0.60

P(X = 4) = ⁴C₄ (0.40)⁴ (0.6)⁴⁻⁴ = 0.0256 = 0.026 to 3 d.p.

B) n = total number of sample spaces = number of generators to be picked = 4

x = Number of successes required = number of defective generators required = 0

p = probability of success = probability that a randomly selected generator is defective = (4/10) = 0.40

q = probability of failure = probability that a randomly selected generator is NOT defective = 1 - p = 1 - 0.40 = 0.60

P(X = 0) = ⁴C₀ (0.40)⁰ (0.6)⁴⁻⁰ = 0.1296 = 0.130 to 3 d.p.

Hope this Helps!!!

8 0
3 years ago
What is the modulus of 2 – 3i?
Firlakuza [10]
<span>Approx.- 3.606
</span> |a + bi| = √<span>a^2 + b^<span>2</span></span>
4 0
3 years ago
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"how many ways are there to construct a string of 3 digits if numbers cannot be repeated
solniwko [45]
There are 10 total digits ( 0, 1 , 2, 3, 4, 5, 6, 7,8 ,9)

1st digit can be 1 of 10
2nd digit can be 1 of 9 ( 10-1 because a number cannot repeat)
3rd digit can be 1 of 8 ( 9-1 because no number can repeat)

total combinations = 10 * 9 * 8 = 720
8 0
3 years ago
Read 2 more answers
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