First, pretend the semicircle isn't cut out of the triangle and find the area of that equilateral triangle using the equation:
![a = \frac{ \sqrt{3} }{4} {l}^{2}](https://tex.z-dn.net/?f=a%20%3D%20%20%5Cfrac%7B%20%5Csqrt%7B3%7D%20%7D%7B4%7D%20%7Bl%7D%5E%7B2%7D%20)
where l=the length of one side of the triangle (2+2+4=8mm).
Then find the area of the semicircle using the equation for the area of a circle:
![a = \pi {r}^{2}](https://tex.z-dn.net/?f=a%20%3D%20%5Cpi%20%7Br%7D%5E%7B2%7D%20)
where r=the radius of the circle (4/2=2mm) and then dividing the area you get by 2 to get the area of the semicircle.
Finally subtract the area you got for semicircle from the area of the entire equilateral triangle.
Step-by-step explanation:
y = x-3
So, y + 3 = x
x = y + 3
if x = 7
y = 7 - 3 = 4
if y = 1
x = 1 + 3 = 4
......
The first answer would go into the 3rd slot, the second one goes into the fourth, the third one goes into the first slot, and the last one goes into the second slot
Ik that it isn’t one I think it is three and Ik it is the last one I think that is that right one