A = 2+3a +6
a-3a = 8
-2a = 8
a = -8/2 = -4
30*(100%+40%)
30*140%
140% as a decimal is (140/100) which is 1.4
30*1.4=42
42/120=0.32.
Ali should sell each can for $0.32
Hope this helps :)
(x - 3) + (x - 6) + x = 63
x - 3 + x - 6 + x = 63
Combine like terms
3x - 9 = 63
Isolate the constant
3x - 9 + 9 = 63 + 9
3x = 72
Isolate the viable
3x / 3 = 72 / 3
x = 24
Answer:
The 20th percentile of coffee temperature is 155.4532 degrees Fahrenheit.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 160 degrees
Standard Deviation, σ = 5.4 degrees
We are given that the distribution of temperature of coffee is a bell shaped distribution that is a normal distribution.
Formula:
We have to find the value of x such that the probability is 0.2
Calculation the value from standard normal z table, we have,
Thus,

The 20th percentile of coffee temperature is 155.4532 degrees Fahrenheit.
If QR is a median, then:

We have NO = 30, MP = 9x - 42 and QR = x + 15. Substitute:

<h3>Answer: A. 6</h3>