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irina [24]
3 years ago
7

Tanya drove 3 1/2 hours and used 1/3 tank of gas. For how long could Tanya drive using​ 1/2 ​tank of gas?

Mathematics
1 answer:
creativ13 [48]3 years ago
4 0
<span>
3 1/2  = 7/2

7/2  hours and used 1/3 tank of gas
</span><span>? hours and used 1/2 tank of gas

1/2 * 7/2
------------
    1/3

= 7/4
-------
  1/3

= 7/4 * 3
= 21/4
= 5 1/4 

answer: 5 1/4 hours </span><span>Tanya could drive using​ 1/2 ​tank of gas</span><span>

</span>
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A jacket is advertised to be 85% off the original price. If the sale price is $102 what is the original price ?
Jobisdone [24]
The answer would prob around $188.70 because .85x102=86.7 so add that to 102 and u get 188.70 but I'm prob wrong and I have a test on this tomorrow 


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3 years ago
Suppose Mahkah makes a Native American lunch in a pot that is shaped like a right cylinder. If
Harman [31]

The pot can hold 5.23 quarts

Step-by-step explanation:

  • Step 1: Find the volume of the right cylinder shaped pot.

Diameter of the pot = 8 in

⇒ Radius = 4 in

Height = 6 in

⇒ Volume of the pot = πr²h = 3.14 × 4² × 6

                                   = 301.44 in³

  • Step 2: Convert inches to quarts.

1 in³ = 0.017316 liquid quarts

⇒ 301.44 in³ = 301.44 × 0.017316 = 5.23 quarts

6 0
3 years ago
The volume of the rectangular prism is 60x^3 + 145x^2 + 70x. Factor to find the possible expressions for length, width and heigh
tester [92]
The volume of the rectangular prism:
V=length\cdot width\cdot height=lwh

60x^3 + 145x^2 + 70x=5x(12x^2+29x+14)\\\\=5x(12x^2+21x+8x+14)=5x[3x(4x+7)+2(4x+7)]\\\\=5x(4x+7)(3x+2)\\\\Answer:\\length=5x\\width=4x+7\\height=3x+2
4 0
3 years ago
The table shows the time a patient spends at the dentist and the amount of the bill.
Alla [95]

Answer:

Correlation coefficient for the data in the table was found to be 0.93

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Each of these extreme value problems has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to f
tino4ka555 [31]

Answer:

The minimum value of the given function is f(0) = 0

Step-by-step explanation:

Explanation:-

Extreme value :-  f(a, b) is said to be an extreme value of given function 'f' , if it is a maximum or minimum value.

i) the necessary and sufficient condition for f(x)  to have a maximum or minimum at given point.

ii)  find first derivative f^{l} (x) and equating zero

iii) solve and find 'x' values

iv) Find second derivative f^{ll}(x) >0 then find the minimum value at x=a

v) Find second derivative f^{ll}(x) then find the maximum value at x=a

Problem:-

Given function is f(x) = log ( x^2 +1)

<u>step1:</u>- find first derivative f^{l} (x) and equating zero

  f^{l}(x) = \frac{1}{x^2+1} \frac{d}{dx}(x^2+1)

f^{l}(x) = \frac{1}{x^2+1} (2x)  ……………(1)

f^{l}(x) = \frac{1}{x^2+1} (2x)=0

the point is x=0

<u>step2:-</u>

Again differentiating with respective to 'x', we get

f^{ll}(x)=\frac{x^2+1(2)-2x(2x)}{(x^2+1)^2}

on simplification , we get

f^{ll}(x) = \frac{-2x^2+2}{(x^2+1)^2}

put x= 0 we get f^{ll}(0) = \frac{2}{(1)^2}   > 0

f^{ll}(x) >0 then find the minimum value at x=0

<u>Final answer</u>:-

The minimum value of the given function is f(0) = 0

5 0
3 years ago
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