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3 years ago

What is the value of (-5)^4

Mathematics

1 answer:

Vladimir [108]3 years ago

5 0

Answer:

the answer to your question is 625

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2. Which of these best describes d, the diameter of a circle?

svlad2 [7]

Answer:

Step-by-step explanation:

This value is the ratio of the circumference of a circle to its diameter and is called π (Pi).

answer-F

5 0

3 years ago

Solve the inequality for x. Show each step of the solution.10x > 2(8x – 3) – 18

Luden [163]

Answer: x<4

Given the inequality:

$10x>2(8x-3)-18$

We want to solve the inequality for x.

First, distribute the bracket on the right side of the inequality.

$\begin{gathered} 10x>2(8x)-2(3)-18 \\ 10x>16x-6-18 \\ 10x>16x-24 \end{gathered}$

Next, subtract 10x from both sides of the inequality.

$\begin{gathered} 10x-10x>16x-10x-24 \\ 0>6x-24 \end{gathered}$

Add 24 to both sides of the inequality.

$\begin{gathered} 0+24>6x-24+24 \\ 24>6x \end{gathered}$

Divide both sides of the inequality by 6.

$\begin{gathered} \frac{24}{6}>\frac{6x}{6} \\ 4>x \\ \implies x$

The solution to the inequality is x<4.

6 0

1 year ago

Write seven hundred two and six hundred fifty-six thousandths in standard form and in expanded form.

Naddik [55]

Standard Form: 702.656
Expanded Form: 700+2+0.6+0.05+0.006

7 0

3 years ago

Two different box-filling machines are used to fill cereal boxes on an assembly line. The critical measurement influenced by the

defon

Answer:

0.1981

Step-by-step explanation:

See attachment for calculation

5 0

3 years ago

webassign If a snowball melts so that its surface area decreases at a rate of 6 cm2/min, find the rate at which the diameter dec

drek231 [11]

Answer:

The answer is $\frac{3}{10\pi } cm/min$

Step-by-step explanation:

Assuming the snowball is a perfect sphere, then if A denotes the surface area and D the diameter then:

$A=4\pi r^{2} = 4\pi (\frac{D}{2} )^{2} =\pi D^{2}$

Differentiating wrt r we have:

$\frac{dA}{dD} =2\pi D$

We are told that $\frac{dA}{dt}= -6$ and we want to find $\frac{dD}{dt}$

By the chain rule we have:

$\frac{dA}{dD}=\frac{dA}{dt}.\frac{dt}{dD}=\frac{\frac{dA}{dt} }{\frac{dD}{dt} }$

∴ $2\pi D=-\frac{6}{\frac{dD}{dt} }$

∴ $\frac{dD}{dt}=-\frac{6}{2\pi D}$

When D=10 then

$\frac{dD}{dt} =-\frac{6}{10*2\pi } =-\frac{3}{10\pi }$

The sign (-) shows that the D is decreasing.

3 0

3 years ago