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2 years ago

Hhhhhhhhhhhheeeeeeeeeeeeeeeeeeeeelllllllllllllllllp

Mathematics

2 answers:

alexdok [17]2 years ago

8 0

Answer:

Step-by-step explanation:10 percent of 50 is 5 +50 equals 55

aleksklad [387]2 years ago

4 0

Answer:

$55

Step-by-step explanation:

Find how much is 10% of 50 which is 5 and add it to the cost to store.

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Two containers hold several balls. Once a second, one of the balls is chosen at random and switched to the other container. Afte

natka813 [3]

Answer:

(a) 8 balls

(b) 4 balls

Step-by-step explanation:

Let

$N \to$ Number of balls

For a box, the probability that there are N balls in it is:

$Pr = 0.5^N$

For 2 boxes, it is:

$Pr = 2 * 0.5^N$

From the question, we have:

$\frac{80}{10000} \to$ Favorable outcome

To solve for N, we have:

$2 * 0.5^N = \frac{80}{10000}$

$2 * 0.5^N = 0.008$

Divide both sides by 2

$0.5^N = 0.004$

Take log of both sides

$\log(0.5^N) = \log(0.004)$

Apply law of logarithm

$N\log(0.5) = \log(0.004)$

Make N the subject

$N = \frac{\log(0.004)}{\log(0.5)}$

$N =7.966$

Approximate

$N = 8$

Solving (b): Balls in one of the two boxes.

Here, we assume that each ball will have almost the same number of balls at a given instance;

Hence, we have:

$Balls \approx \frac{N}{2}$

$Balls \approx \frac{8}{2}$

$Balls \approx 4$

<em>4 balls in each box</em>

6 0

3 years ago

A phycologist is interested in determining the proportion of algae samples from a local rivulet that belong to a particular phyl

LuckyWell [14K]

Answer:

A sample of 16577 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a p-value of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

She wants to estimate the proportion using a 99% confidence interval with a margin of error of at most 0.01. How large a sample size would be required?

We have no estimation for the proportion, and thus we use $\pi = 0.5$ , which is when the largest sample size will be needed.