<u>Answer:</u> $42546.9 will be the earning in 4 years.
<u>Step-by-step explanation:</u>
The equation for compound interest follows:
![A=P(1+\frac{r}{100})^n](https://tex.z-dn.net/?f=A%3DP%281%2B%5Cfrac%7Br%7D%7B100%7D%29%5En)
where,
A = total amount
P = Principle amount
r = rate of interest
n = number of years
We are given:
Earnings earned per month = $3250
Earnings earned per year = ($3250 × 12) = $39000
The values become:
![P=\$39000\\r=2.2\%\\n=4yrs](https://tex.z-dn.net/?f=P%3D%5C%2439000%5C%5Cr%3D2.2%5C%25%5C%5Cn%3D4yrs)
Putting values in above equation, we get:
![A=39000(1+\frac{2.2}{100})^4\\\\A=\$ 42546.9](https://tex.z-dn.net/?f=A%3D39000%281%2B%5Cfrac%7B2.2%7D%7B100%7D%29%5E4%5C%5C%5C%5CA%3D%5C%24%2042546.9)
Hence, $42546.9 will be the earning in 4 years.
Answer:
Read below for each answer! (^-^)
Step-by-step explanation:
1: You got the first one right. The explanation does explain why but think about 0 as the surface of the water to better understand.
2: -3; it is between 2 and 4 with only one line through it meaning that it is -3.
3: 7. That's the greatest number both can divide into it.
4: The last one. Any positive number is greater than a negative one and peanut butter's freezing point is positive while the other one's is not.
5: You got it right again! -(-1) has two negatives. Two negatives (mostly) make a positive. So positive 1! Now describe that on a number line.
Hope this helps!
Answer: (4, -9)
<u>Step-by-step explanation:</u>
Use elimination method. Manipulate one (or both) equations to eliminate one of the variables and solve for the remaining variable. <em>I will be eliminating y</em>
6x + y = 15 → 2(6x + y = 15) → 12x + 2y = 30
-7x - 2y = -10 → 1(-7x + 2y = -10) → <u> -7x - 2y = -10</u>
5x = 20
x = 4
Next, replace "x" with "4" into either equation and solve for y.
6(4) + y = 15
24 + y = 15
y = -9
<u>Check:</u>
Plug in x = 4 and y = -9 into the other equation to verify it makes a true statement.
-7x - 2y = -10
-7(4) - 2(-9) = -10
-28 - -18 = -10
-28 + 18 = -10
-10 = -10 ![\checkmark](https://tex.z-dn.net/?f=%5Ccheckmark)
104.12 < 104.20
104.20 is greater than 104.12