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2 years ago

X−6y=19 solve for y.

Mathematics

1 answer:

Mrac [35]2 years ago

5 0

Answer: y= - 19/6+x/6

Step-by-step explanation: maybe

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|6x|+3=21 solve for X (absolute value)

Fudgin [204]

Answer:

$x=3\text{ or } x=-3$

Step-by-step explanation:

So we have the equation:

$|6x|+3=21$

First, subtract 3 from both sides:

$|6x|=18$

Definition of absolute value:

$6x=18\text{ or } 6x=-18$

Divide both sides by 6 for both equations:

$x=3\text{ or } x=-3$

And we're done!

6 0

2 years ago

Read 2 more answers

I have 7 hundreds blocks, 5 tens blocks, and 8 ones blocks. I use my blocks to model two 3-digit numbers. What could my two numb

lawyer [7]

There 7 blocks of hundreds which means each such block is equivalent to 100.
There are 5 blocks of tens, which means each such block is equivalent to 10.
There are 8 blocks of ones, which means each such block is equivalent to 1.

The total of these blocks will be = 7(100) + 5(10) + 8(10) = 758

We can make several two 3-digit numbers from these blocks. An example is listed below:

Example:
Using 3 hundred block, 2 tens blocks and 4 ones block to make one number and remaining blocks to make the other number. The remaining blocks will be 4 hundred blocks, 3 tens blocks and 4 ones blocks
The two numbers we will make in this case are:

1st number = 3(100) + 2(10) + 4(1) = 324
2nd number = 4(100) + 3(10) + 4(1) = 434

The sum of these two numbers is = 324 + 434 = 758
i.e. equal to the original sum of all blocks.

This way changing the number of blocks in each place value, different 3 digit numbers can be generated.

5 0

2 years ago

7-c<1 ?? HELPPPP!!!MEEEeee

sesenic [268]

Answer:

c>6, since a negative coefficient reverses the sign

Step-by-step explanation:

7-c<1

-c<-6

c>6

5 0

3 years ago

A thin tube stretched across a street counts the number of pairs of wheels that pass over it. A vehicle classified as type A wit

aliina [53]

Answer: All possible solutions would be

(1,41), (8,33), (15,25), (22,17), (29,9), (36,1)

Step-by-step explanation:

Let the number of vehicle of type A be 'x'.

Let the number of vehicle of type B be 'y'.

Since we have given that

Number of axles of type A = 2

Number of axles of type B = 9

After 2 hours, number of counts = 101

so, our equation becomes,

$2x+9y=101$

So, all possible solutions would be

(1,41), (8,33), (15,25), (22,17), (29,9), (36,1)

7 0

2 years ago

if a taxi charges $3.50 for the first on-fifth of a mile, then $0.55 cents for each additional one-fifth mile, how far can one t

34kurt

Let's forget for the tie being the cost ($3.5)of the 1st fifth of a mile:

Taxi charge excluding $3.5, is $13.95 - $3.5 = $10.45.

If each of the 5th (1/5) of a mile costs $0.55, then with $10.45 we can drive:
10.45/0.55 = 19 fifth of a mile. Add to that the 1st fifth = 20 fifth of a mile
20 fifth = 20 x 1/5 = 4 miles (answer)

7 0

3 years ago