<em>BD</em> = 56
Step-by-step explanation:
Step 1: In rectangle, the diagonals are congruent and bisect each other.
So, <em>AC</em> = <em>BD</em>
⇒<em>AG</em> + <em>GC</em> = <em>BG</em> + <em>GD</em>
⇒<em>AG</em> + <em>AG</em> = <em>GD</em> + <em>GD</em>
⇒ 2<em>AG</em> = 2<em>GD</em>
⇒<em>AG</em> = <em>GD</em>
⇒ –7<em>j </em>+ 7 = 5<em>j</em> + 43
⇒–7<em>j</em> – 5<em>j</em> = 43 – 7
⇒–12<em>j</em> = 36
⇒<em>j</em> = –3
Step 2: <em>BD</em> = 2<em>DG</em>
<em>BD</em> = 2(5<em>j</em> + 43)
= 2(5 (–3) + 43)
= 2(–15 + 43)
= 2 × 28
= 56
Hence, <em>BD</em> = 56.
Step-by-step explanation:
4x^2-9
=(2x)^2 -3^2
=(2x+3) (2x-3)
Hope this helps you.
Answer:
Area_circle = pi*(24/5)*(360/48)=36pi = 113.097
<span>Best you can do is describe a set:
John
</span>
Answer:
EB = 10
Step-by-step explanation:
For this problem, you can use the power of a point, in the situation where two secants intersect in the interior of a circle. The formula is as follows:
CE * ED = AE * EB
(This is applied specifically to this problem)
We can substitute the values given,
5 * (x - 4) = 3 * x
simplify,
5x - 20 = 3x
and solve.
2x - 20 = 0
2x = 20
x = 10
Since the value of EB is x, EB = 10.
