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olga nikolaevna [1]
3 years ago
6

Plz help meeeeeeeee You must make a constructive response and this is 8th Grade Math

Mathematics
2 answers:
natulia [17]3 years ago
8 0

Answer:

5 \sqrt{18}  -  \sqrt{32}  \\  = 5 \sqrt{9 \times 2}  -  \sqrt{4 \times 4 \times 2} \\  = 5 \times 3 \times  \sqrt{2}   - 2 \times 2 \times  \sqrt{2}  \\  = 15 \sqrt{2}  - 4 \sqrt{2}  \\  =  \boxed{11 \sqrt{2} }

<h3>11√2 is the right answer.</h3>
Natali [406]3 years ago
7 0

Answer:

I'm in 10th grade so I'll see what I can do and will answer to the best of my ability.

Step-by-step explanation:

What Julie did wrong was, she did simplify she just did it wrong. She used 4*8 which does equal 32 but 8 can't be simplified anymore than that. If she would of used 2*16 then her answer would be right.

Hope this helps!

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ivanzaharov [21]
You would first make the fractions improper (making the numerator bigger then the denominator) in order to do that times the denominator with the whole number and add the numerator.
Ex) 3*8 = 24 + 5 = 29/8
Then you would add both of the improper fractions
3 0
3 years ago
What are the x and y intercepts of the equation: 10x + 4y = -20?
snow_tiger [21]

Answer:

x= (-2, 0) y=(0, -5)

Step-by-step explanation:

or you could say -2 and -5

3 0
3 years ago
Will is twice as old as Jill. Three years ago, Jill's age was two fifths of Will's age then. How old is each now?
dimulka [17.4K]
"Will is twice as old as Jill."

                       Jill's age . . . . .   J
                       Will's age . . . . 2J .

"Three years ago . . .

                       Jill's age then . . . . .   J - 3
                       Will's age then . . . . 2J - 3

". . . Jill's age then was 2/5 of Will's age then."

                                         J - 3  =  (2/5) (2J - 3)
Multiply
each side by  5 :          5J - 15  =  2 (2J - 3)

Divide
each side by  2 :          2.5 J - 7.5  =  2J - 3 

Subtract  2J
from each side:            0.5 J - 7.5  =      -3

Add  7.5
to each side:                0.5 J           =     4.5

Multiply
each side by  2 :                J            =       9

Jill is  9  y.o. now.
Will is 18 y.o. now.

4 0
3 years ago
Find the area of the circle to the<br> nearest tenth. Use 3.14 for it<br> (11 mm)
Nikolay [14]

Answer:

The area of the circle is 379.94 mm²

Step-by-step explanation:

To solve this problem we need to use the area formula of a circle:

a = area

r = radius = 11 mm

π = 3.14

a = π * r²

we replace with the known values

a = 3.14 * (11 mm)²

a = 3.14 * 121 mm²

a = 379.94 mm²

Round to the nearest tenth

a = 379.94 mm² = 379.9 mm²  

The area of the circle is 379.9 mm²

4 0
3 years ago
The assignment is about : Subtract Polynomials What i have to do : Subtract the polynomials, showing all the steps necessary to
lawyer [7]
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2. 5x^2 + 3x - 4 - (x^2 - 6x)...same thing..distribute
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6 0
3 years ago
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