Ok so student in cleveland walks 2.5 miles away from cleveland every hour from 8
so the distance, x is x=2.5t
the riding one rides 4 hours later, so t-4
11 mph
y=11(t-4)
A. x=2.5t
y=11(t-4)
when do they meet is when the distance when they are equal or when x=y
2.5t=x=y=11(t-4)
solve for t
2.5t=11(t-4)
2.5t=11t-44
-8.5t=-44
divide both sides by -8.5
t=5.17647
answer is 5.18 hours
A.
x=2.5t
y=11(t-4)
B. 5.18 hours
Answer:
y-5 = -3x
or
y = -3x+5
Step-by-step explanation:
We can use the point slope form of the equation
y-y1 = m(x-x1) where m is the slope and (x1,y1) is a point on the line
y-5 = -3(x-0)
y-5 = -3x
We can change it to slope intercept form y= mx+b by adding 5 to each side
y-5+5 = -3x+5
y = -3x+5
Answer:
x = -80
Explanation
-40 divided by 1/2 is -80
Since x can be any value as long as the denominator equals 0 (it doesn't matter if it's positive or negative), we have to figure out when x^2=0, which is when x=0. Therefore, the domain is (-inf, 0) U (0, inf)
D*pi so 6cm * pi which is ~18.849cm
